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- Question
- A boy walking at a speed of 15 km/h reaches his school 20 min late. Next time he increases his speed by 5 km/h but still he late by 5 min. Find the distance of the school from his home.?
Options- A. 5 km
- B. 10 km
- C. 15 km
- D. 20 km
- Correct Answer
- 15 km
ExplanationLet the distance = x
Here, the difference in time
= 20 - 5 = 15 min
= 15/60 = 1/4h
Speed during next journey
= 15 + 5 = 20 km/h
According to the question,
x/15 - x/20 = 1/4
? 4x - 3x/60 = 1/4
? x = 60/4 = 15
? x = 15 km - 1. Mohan walking at a speed of 20 km/h reaches his office 1 h late. Next time he increases his speed by 5 km/h, then he reaches his office 30 min early. What is the distance of his office from his house?
Options- A. 100 km
- B. 125 km
- C. 150 km
- D. None of the above Discuss
- 2. A person covers half of his journey at 40 km/h, one-third at 60 km/h and rest of journey at 30 km/h. Find his average speed for the whole journey.?
Options- A. 45 km/h
- B. 42. 35 km/h
- C. 50 km/h
- D. 40 km/h Discuss
- 3. A walks at a uniform rate of 2 km/h and 2 h after his start, B cycles after him at the uniform rate of 5 km/h. How far from the starting point will B catch A?
Options- A. 62/3 km
- B. 61/3 km
- C. 65/7 km
- D. 63/7 km Discuss
- 4. A man riding a bicycle form his house at 10km/h and reaches his office late by 6 min. He increases his speed by 2km/h and reaches 6 min before. How far is the office form his house?
Options- A. 6 km
- B. 7 km
- C. 12 km
- D. 16 km Discuss
- 5. A man covers a certain distance on scooter. Had he moved 3 km/h faster, he would have taken 40 min less. If he had moved 2 km/ slower, he would have taken 40 min more. The distance (in
km) is?
Options- A. 42.5
- B. 36
- C. 37.5
- D. 40 Discuss
- 6. For every 4 leaps taken by a dog, a cat takes 5 leaps in the same time. But distance covered in 3 leaps of dog is same as that of 4 leaps of cat. Then what is the ratio of speed of dog and cat?
Options- A. 15 : 14
- B. 16 :15
- C. 12 :11
- D. 10 : 9 Discuss
- 7. Suresh traveled 1200 km by air which formed (2/5) of his trip. One-third of the whole trip he traveled by car And the rest of the journey he performed by train. The distance traveled by train was?
Options- A. 1600 km.
- B. 800 km.
- C. 1800 km.
- D. 400 km. Discuss
- 8. Two cyclists A and B start from the same place at the same time. One going toward north at 18 km/hr. and other going toward south at 20 km/hr. What time will they take to be 95 km. apart?
Options- A. 4 hrs. 30 min.
- B. 4 hrs. 45 min.
- C. 5 hrs.16 min.
- D. 2hrs. 30 min Discuss
- 9. A bullock cart has to cover a distance of 80 km. in 10 hours. If it cover half of journey in 3/5 th time, what should be its speed to cover the remaining distance in time left?
Options- A. 8 km/hr.
- B. 20 km/hr.
- C. 6.4 km/hr.
- D. 10 km/hr. Discuss
- 10. The ratio between the rates of travelling of A and B is 2:3 and therefore A takes 10 min. more than the time taken by B to reach a destination, if A had walked at double the speed, he would have covered the distance in?
Options- A. 30 min
- B. 25 min
- C. 15 min
- D. 20 Min Discuss
Time and Distance problems
Search Results
Correct Answer: 150 km
Explanation:
Distance of his office from his house = {ab/(b - a)} x (t1 + t2)
Here, a = 20 km/h, t1 = 1 h, b = 20 + 5 = 25 km/h
and t2 = 30 min = 0.5 h
? Distance = {20 x 25/(25 - 20)} x (1 + 0.5) = 500(1.5)/5
= 100 x 1.5 = 150 km
Correct Answer: 42. 35 km/h
Explanation:
Let total distance be 100 km.
Then, Average = 100/[ (50/40) + (30/60) + (20/30)]
= 100/( 5/4 + 1/2 + 2/3) = 100/[(15 + 6 + 8)/12]
= (100 x 12)/29
= 42.35
Correct Answer: 62/3 km
Explanation:
Let B catches A after T h.
Then, distance travelled by A in (T + 2) h = Distance travelled by B in T h
According to the question,
2 (T + 2 ) = 5T
? 2T + 4 = 5T
? 3T = 4
? T = 4/3 h
Distance travelled by B in 4/3 h
= (4/3) x 5 = 20/3 = 62/3 km
Correct Answer: 12 km
Explanation:
Here, a = 10 km/h
b = ( 10 + 2 ) = 12 km/h,
t1 = 6 min = 1/10 h
and t2= 1/10 h.
? Required distance = ab( t1 + t2 )/(b - a)
= 10 x 12 x ( 1/10 + 1/10 ) /(12 - 10) = (10 x 12 x 1)/(5 x 2) = 12km
Correct Answer: 40
Explanation:
Let distance and original speed of the man be d km and s km/h.
Then,
d/s - d/s + 3 = 2/3
? [d(s + 3 - s)]/[s(s + 3)] = 2/3
? 9d = 2s(s + 3) ...(i)
And d/(s - 2) - d/s = 2/3
? [d(s - s + 2)]/[s(s - 2)] = 2/3
? 3d = s(s - 2) ...(ii)
From Eqs.(i) and (ii), we get
3s(s - 2) = 2s(s + 3)
? 3s2 - 6s = 2s2 + 6s
? s2 = 12s
? s = 12
From Eq.(ii), we get
3d = 12(12 - 2)
? d = 40 km
Correct Answer: 16 :15
Explanation:
Let distance covered by dog in 1 leap is x and
Distance covered by cat in 1 leap is y
Then, 3x = 4y
? x= 4/3y
Now, Ratio of speed of dog and cat = Ratio of distance covered by them in the same time = 4x : 5y
= 16/3y : 5y
= 16 : 15
Correct Answer: 800 km.
Explanation:
Let the total distance be y km.
Then, 2y / 5 = 1200
? y = (1200 x 5) /2 = 3000 km.
Distance traveled by car
= (1/3 X 3000) = 1000 km.
Distance traveled by train
= [3000- (1200 + 1000) ] km.
= 800 km.
Correct Answer: 2hrs. 30 min
Explanation:
Relative velocity = u + v = 18 + 20 = 38 km
They are 38 km. apart in 1 hr.
? They will be 95 km. apart in ( 95 / 38) hrs.
= 2 hrs . 30 min
Correct Answer: 10 km/hr.
Explanation:
Distance left = (1/2 x 80 ) km. = 40km.
Time left - [(1-3/5) x 10 ] hrs.
= 4 hours
Required speed = (40 / 4 ) km/hr
= 10 km/hr.
Correct Answer: 15 min
Explanation:
Ratio of times taken by A and B = 1/2 : 1/3
Suppose B takes Tb min. Then A takes (Tb + 10) min.
? (Tb + 10 ) : Tb = 1/2: 1/3
? (Tb + 10)/Tb = 3 / 2
? 2Tb + 20 = 3Tb
? Tb = 20
? Time taken by A = 20 +10
= 30 minute
If A had walked at double speed
Req . time = 30/2
=15 minute
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