Let speed of Kapil in still water = x
and speed of the current= y
? Speed upstream = (x - y)
and speed downstream = (x + y)
According to the question,
12/(x - y) - 12/(x + y) = 6
? 6(x2 - y2) = 24y
? x2 - y2 = 4y
? x2 = 4y + y2 ....(i)
Again, 12/(2x - y) - 12/(2x + y) = 1
? 4x2 - y2 = 24y
? x2 = (24y + y2)/4 ....(ii)
From Eqs. (i) and (ii), we get
4y + y2 = (24y + y2)/4
? 16y +4y2 = 24y + y2
? 3y2 = 8y
? y = 8/3 = 22/3 mile/h
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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