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- Question
- Ram and Sita are walking towards each other with the speed of 8 km/h and 2 km/h, respectively over a road 160 km long. How soon will they meet?
Options- A. 16 h
- B. 8 h
- C. 10 h
- D. 20 h
- Correct Answer
- 16 h
ExplanationDistance = 160 km
Relative Speed = 8 + 2 = 10
Time = Distance/Relative speed = 160/10 = 16 h - 1. A man walks 7.5 km at a speed of 3 km/h. At what speed would the man need two walk during the next 2 h to have an average of 4 km/h for the entire session?
Options- A. 3.65 km/h
- B. 4.75 km/h
- C. 5.25 km/h
- D. 6.50 km/h Discuss
- 2. A man in car notices that he can count 25 telephone posts in 1 min. If they are known to be 40 m apart, then at what speed is the car travelling?
Options- A. 52.4 km/h
- B. 57.6 km/h
- C. 48.2 km/h
- D. 44.9 km/h Discuss
- 3. A man performs 2/25 of his total journey by bus, 21/50 by car and the remaining 2 km on foot. Find the total distance covered in the whole journey.?
Options- A. 4 km
- B. 2.7 km
- C. 3.4 km
- D. 3.8 km Discuss
- 4. One local and another express train were proceeding in the same direction on parallel tracks at 29 km/h and 65 km/h, respectively. The driver of the former noticed that it took exactly 16 s for the faster train to pass by him. What is the length of the faster train?
Options- A. 60 m
- B. 120 m
- C. 160 m
- D. 240 m Discuss
- 5. The ratio between the speed of Menna and Tenna is 2 : 3. Meena takes 20 min more than Tenna to walk from A to B. If Menna had walked at double the speed, find the time she would take to from A to B.?
Options- A. 30 min
- B. 60 min
- C. 45 min
- D. 110 min Discuss
- 6. Two train leaves New Delhi at the same time. One travels towards North at 60 km/h and the other travels towards South at 40 km/h . After how many hours will the trains be 150 km apart?
Options- A. 3/2 h
- B. 4/3 h
- C. 3/4 h
- D. 15/2 h Discuss
- 7. Walking 5/7 of his usual rate, a boy reaches his school 6 min late. Find his usual time to reach the school?
Options- A. 10 min
- B. 12 min
- C. 15 min
- D. 18 min Discuss
- 8. A car during its journey travels 30 min at a speed of 40 km/h, another 45 min at a speed of 60 km/h and 2 h at a speed of 70 km/h. Find its average speed?
Options- A. 58 km/h
- B. 63 km/h
- C. 67 km/h
- D. 71 km / h Discuss
- 9. A train running at 8/11 of its own speed reached a place in 5 1/ 2 h. How much time could be saved, if the train would have run as its own speed?
Options- A. 21/2 h
- B. 2 h
- C. 11/2 h
- D. 1 h Discuss
- 10. Starting from his house, one day a student walks at a speed of 3 km/h and reaches his school 5 min late. Next day he increases his speed by 1 km/h and reaches the school 3 min early. How far is the school from his house?
Options- A. 1.6 km
- B. 1.24 km
- C. 1.36 km
- D. 1.8 km Discuss
Time and Distance problems
Search Results
Correct Answer: 5.25 km/h
Explanation:
Let speed of walking be V km/h.
Total time taken = (7.5/3) + 2 = 4.5 h
Total distance covered = (7.5 + 2V) km
? (7.5 + 2V)/4.5 = 4
? 7.5 + 2V = 18
? 2V = 10.5
? V = 5.25
? Speed of walking = 5.25 km/h
Correct Answer: 57.6 km/h
Explanation:
Number of gaps between 25 telephone posts = 24
Distance travelled in 1 min = 40 x 24 = 960 m
Speed = (960 x 60)/1000 = 57.6 km/h
Correct Answer: 4 km
Explanation:
Let total distance covered in the whole journey = L km
? 2L/25 + 21L/50 + 2 = L
? L = 4
? Total distance covered = 4 km
Correct Answer: 160 m
Explanation:
Relative speed of express train to local train = 65 - 29 = 36 km/h
= 36 x (5/18) m/s = 10 m/s
? Length of faster train = 10 x 16 = 160 m
Correct Answer: 30 min
Explanation:
Since, ratio of speeds of Meena and teena is 2 : 3.
? Ratio of time taken = 3 : 2
If, Teena takes x min to walk from A to B, then Meena takes (x + 20) min.
? (x + 20)/x = 3/2 ? 2x + 40 = 3x
? x = 40 min
Hence, Meena takes 60 min walking at her usual speed and at double the speed, she would take 30 min.
Correct Answer: 3/2 h
Explanation:
Relative speed = 60 + 40 = 100 km/h
Time = Distance/speed = 150/ 00 = 3/2 h
Correct Answer: 15 min
Explanation:
Since, the boys now walks at 5/7 of usual speed, so he will take 7/5 of his usual time.
? Extra time = (7/5 - 1) x Usual time = 6 min (known)
? 2/5 x Usual time = 6
? Usual time = 15 min
Correct Answer: 63 km/h
Explanation:
Average speed = [(30/60) x 40 + (45/60) x 60 + (2 x 70)] / [(30/60) + (45/60) + 2]
= (20 + 45 + 140)/[(30 + 45 + 120)/60]
= (205/195) x 60 km/h
= 63.07 km/h
= 63 km/h
Correct Answer: 11/2 h
Explanation:
New speed = 8/11 of usual speed
New time = 11/8 of usual time
? 11/8 of usual time = 11/2 h
? Usual time = (11 x 8)/(2 x 11) = 4 h
? Time saved = 51/2- 4
= 11/2
Correct Answer: 1.6 km
Explanation:
Let the distance be D km
Difference in timings = 8 min = 8/60 h = 2/15 h
? D/3 - D/4 = 2/15
? D/12 = 2/15
? D = 2 x 12/15 = 1.6 km
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