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- Question
- The average speed of a train in the onward journey is 25% more than that of the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and fro journey is 17 h covering a distance of 800 km. The speed of the train in the onward journey, is?
Options- A. 45 km/h
- B. 47.06 km/h
- C. 50.00 km/h
- D. 56.25 km/h
- Correct Answer
- 56.25 km/h
ExplanationLet the speed of the train during returning journey be x km/h
Speed during onward journey = x + 25x/100 = 5x/4 km/h.
Distance coverd in onward journey = 800 / 2 = 400 km
Total time taken = Covered distance / Speed
Time taken by train in onward journey = 400/(5x/4)
and time taken in returning journey = 400/x
Thus, 400/(5x/4) + 400/x = 16
? 320/x + 400/x = 16
? 16x = 720
? x = 45 km/h
Speed of the train in the onward journey = 5 x 45/4 = 56.25 km/h - 1. Running at a speed of 60 km/h, a train passed through a 1.5 km long tunnel in 2 min. What is the length of the train?
Options- A. 250 m
- B. 500 m
- C. 1000 m
- D. 1500 m Discuss
- 2. Anurag traveled a distance of 45 km in 8 h 45 min. He traveled partly on foot at 3 km/h and partly by bicycle at 8 km/h .The distance traveled on the bicycle, is?
Options- A. 25 km
- B. 15 km
- C. 30 km
- D. 20 km Discuss
- 3. A train leaves manipur at 6:00 am and reaches Dispur at 10:00 am. Another train leaves Dispur at 8:00 am and reaches Manipur at 11:00 am. At what time do the two trains cross each
other?
Options- A. 7 : 56 am
- B. 7 : 56 pm
- C. 8 : 56 am
- D. 8 : 56 Discuss
- 4. X and Y start walking towards each other at 8:00 am at the speeds of 3 km/h and 4 km/h, respectively. They were initially 17.5 km apart. At what time do they meet?
Options- A. 10 : 30 am
- B. 10 : 30 pm
- C. 11 : 30 am
- D. 11 : 30 pm Discuss
- 5. A car crosses a man walking at 6 km/h. The man can see the things up to 450m only in one direction due to fog. He sees the car which was going in the same direction for 4.5 minutes. What is the speed of the car?
Options- A. 9 km/h
- B. 12 km/h
- C. 12.5 km/h
- D. 15 km/h Discuss
- 6. The ratio between the speed of Menna and Tenna is 2 : 3. Meena takes 20 min more than Tenna to walk from A to B. If Menna had walked at double the speed, find the time she would take to from A to B.?
Options- A. 30 min
- B. 60 min
- C. 45 min
- D. 110 min Discuss
- 7. One local and another express train were proceeding in the same direction on parallel tracks at 29 km/h and 65 km/h, respectively. The driver of the former noticed that it took exactly 16 s for the faster train to pass by him. What is the length of the faster train?
Options- A. 60 m
- B. 120 m
- C. 160 m
- D. 240 m Discuss
- 8. A man performs 2/25 of his total journey by bus, 21/50 by car and the remaining 2 km on foot. Find the total distance covered in the whole journey.?
Options- A. 4 km
- B. 2.7 km
- C. 3.4 km
- D. 3.8 km Discuss
- 9. A man in car notices that he can count 25 telephone posts in 1 min. If they are known to be 40 m apart, then at what speed is the car travelling?
Options- A. 52.4 km/h
- B. 57.6 km/h
- C. 48.2 km/h
- D. 44.9 km/h Discuss
- 10. A man walks 7.5 km at a speed of 3 km/h. At what speed would the man need two walk during the next 2 h to have an average of 4 km/h for the entire session?
Options- A. 3.65 km/h
- B. 4.75 km/h
- C. 5.25 km/h
- D. 6.50 km/h Discuss
Time and Distance problems
Search Results
Correct Answer: 500 m
Explanation:
Suppose length of the train = L m
Speed of the train = 60 km/h = 60 x 1000 = 60000 m/h
Length of tunnel = 1.5 km = 1500 m
Time taken by train = 2 min = 1/30 h
Time = Distance/Speed
? 1/30 = L + 1500/60000
? l = 500 m
Correct Answer: 30 km
Explanation:
Let the distance traveled on foot be x km
Then, distance converted by bicycle = (45 - x) km
? x/3 + (45 -x) /8 = 83/4 = 35/4
? (8x + 135 - 3x)/24 = 35/4
? 5x + 135 = 210
? 5x = 75
? x = 15
? Distance converted by bicycle = (45 - 15) = 300 km
Correct Answer: 8 : 56 am
Explanation:
Let distance between Manipur and Dispur = D km
Average speed of train from Manipur = D/4 km/h
Average speed of train from Dispur = 2D/7 km/h
Let they meet T h after 6:00 am.
Then, according to the question,
(D/4 x T) + 2D/7 x (T - 2) = D
? T/4 + 2(T - 2)/7 = 1
? 7T + 8(T - 2) = 28
? 15T = 44
? T = 44/15 h = 2h 56 min
Clearly, trains meet 2 h 56 min after 6:00 am.
It means the trains meet at 8:56 am.
Correct Answer: 10 : 30 am
Explanation:
Let they meet after x h.
Then, according to the question,
3x + 4x = 17.5
? 7x = 17.5
? x = 17.5 / 7 = 2.5 h
So, they meet 2.5 h after 8:00 am.
It means they meet at 10:30 am.
Correct Answer: 12 km/h
Explanation:
Time = Total distance / Relative speed
4.5/60 hr. = (450/1000) / x
? x = 6 km/h
Relative speed = Speed of car - Speed of man
6 = x - 6
? x = 12 km/h
Correct Answer: 30 min
Explanation:
Since, ratio of speeds of Meena and teena is 2 : 3.
? Ratio of time taken = 3 : 2
If, Teena takes x min to walk from A to B, then Meena takes (x + 20) min.
? (x + 20)/x = 3/2 ? 2x + 40 = 3x
? x = 40 min
Hence, Meena takes 60 min walking at her usual speed and at double the speed, she would take 30 min.
Correct Answer: 160 m
Explanation:
Relative speed of express train to local train = 65 - 29 = 36 km/h
= 36 x (5/18) m/s = 10 m/s
? Length of faster train = 10 x 16 = 160 m
Correct Answer: 4 km
Explanation:
Let total distance covered in the whole journey = L km
? 2L/25 + 21L/50 + 2 = L
? L = 4
? Total distance covered = 4 km
Correct Answer: 57.6 km/h
Explanation:
Number of gaps between 25 telephone posts = 24
Distance travelled in 1 min = 40 x 24 = 960 m
Speed = (960 x 60)/1000 = 57.6 km/h
Correct Answer: 5.25 km/h
Explanation:
Let speed of walking be V km/h.
Total time taken = (7.5/3) + 2 = 4.5 h
Total distance covered = (7.5 + 2V) km
? (7.5 + 2V)/4.5 = 4
? 7.5 + 2V = 18
? 2V = 10.5
? V = 5.25
? Speed of walking = 5.25 km/h
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