Let the distance traveled on foot be x km
Then, distance converted by bicycle = (45 - x) km
? x/3 + (45 -x) /8 = 83/4 = 35/4
? (8x + 135 - 3x)/24 = 35/4
? 5x + 135 = 210
? 5x = 75
? x = 15
? Distance converted by bicycle = (45 - 15) = 300 km
Given in the question,
Points (a, b) and [(a + 3), (b + k)] will satisfy the equation x ? 3y + 7 = 0.
Points (a, b) in the equation x ? 3y + 7 = 0, We will get
? a ? 3b + 7 = 0 ...................... (i)
Points (a + 3), (b + k) in the equation x ? 3y + 7 = 0, We will get
a + 3 ? 3 (b + k) + 7 = 0
? a + 3 ? 3b ? 3 k + 7 = 0 (Rearrange the equation)
? a ? 3b + 7 + 3 ? 3 k = 0 (a ? 3b + 7 = 0 , Put the value from Equation (1) ), We will get
? 0 + 3 ? 3k = 0
? 3k = 3
? k = 1
If ?0.03 x 0.3 a = 0.03 x 0.3 x ? b then value of |
|
is |
b |
CP of 6 toffees = ? 1,
SP of 6 toffees = 150% of 1 = 150/100 = 3/2
? For ? 3/2, the number of toffees sold = 6
? For ? 1, the number of toffees sold = 6 x (2/3) = 4
Given :- ?A = x° , ?B = y° , ?C = ( y + 20 )° and 4x ? y = 10
We know that , ?A + ?B + ?C = 180°
? x + y + ( y + 20 ) = 180°
? x + 2y = 180 - 20 = 160° ........... ( ? )
4x ? y = 10 ........... ( ? )
From ( ? ) and ( ? ) , we get
? y = 70 , x = 20
? The angles of the triangle are 20° , 70° , 90° .
Hence , the triangle will be Right-angle triangle .
Let the two numbers be x and y.
Then, x2 + y2 = 234 ...(i)
and (x - y)2 = 144 ...(ii)
Now, (x - y)2 = 144
? x2 + y2 - 2xy = 144
? 234 - 2xy = 144 [using Eq.(i)]
On substituting the value of x2 + y2 from Eq.(i) in Eq.(ii),
we get
2xy = 90
? xy = 45
So, the product of the two numbers is 45.
Let CP Rs. x
Then, (110x / 100) - (75x / 100) = 21
? 35x = 2100
? x = Rs. 60
P.W. of Rs. 360 due 2 years hence at 71/7% per annum
= Rs. { {100 x 360} / {100 + (50/7 x 2)}}
= Rs. { (100 x 360 x 7) / 800} = Rs. 315
? S.P. = Rs. 315
Hence, gain % = (15 x 100) / 300 = 5%
Total C.P.of 200 kg of sugar = Rs. (80 x 6.75 + 120 x 8)
= Rs. (500 + 960)
= Rs. 1460
C.P. of 1 kg = Rs. 1460 / 200 = Rs. 7.30
Gain required = 20%
? S.P. of 1 kg = (120% of Rs. 7.30)
= Rs. (120/100) x 7.30
= Rs. 8.76 per kg
C.P. of B = 110% of Rs. 10000 = Rs. 11000
Loss of B = 10%
S.P. of B = 90% of Rs. 11000 = Rs. 9900
Thus, C.P. of A = Rs. 9900
So, A gets [(10% of Rs. 10000) + (10000 - 9900)] = Rs. 1100
? S.P. = Rs. 54000
Gain earned = 20%
? C.P. = Rs. (100/120) x 54000 = Rs. 45000
Now, S.P. = Rs. 45000
And Loss = 10%
? Original C.P. = Rs. (100/90) x 45000 = Rs. 50000
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