speed of a train in kilometer per hour =45
Speed in meter per second = ( 5/18 ) x Speed in kilometer per hour
= 45 x 5/18
= 12.5 kmph
At 3/4 of the usual speed, the time taken is 4/3 of the usual time
? 4/3 of usual time - usual time = 20 min
? 4x/3 - x = 20
? x/3 = 20
? x = 60 min.
Average speed = 2uv / ( u + v ) km/hr
=(2 x 64 x 80) / (64 + 80) km/hr
= (2 x 64 x 80) / 144 km/hr.
= 71.11 km/hr
Ratio of speed = 2 : 3
Ratio of times taken for same distance = 1/2 : 1/3
From question 1/2 : 1/3 = t : 36
? (1/3) x t = (1/2) x 36
? x = 54 min .
Let distance covered by boy is Y.
Then, 25 : 10 : : 1000 : Y
? Y = (10 x 1000)/25 = 400 m
Average speed = 2uv / (u + v)
= ( 2 x 35 x 45) / (35 + 45) km/hr.
= 39 3/8 km/hr
Speed of the motor car in meter per second = 250 / 25
= 10 m/s
Speed in km/hr = (18/5) x speed in m/s
= 10 x (18 / 5) km/hour
=36 km/hour.
W + R = 4 h 20 min
W + W = 5 h 20 min
? R + R = 3 h 20 min
Sd = 12 km/h
Su = 5 km/h
Speed of current = (12 - 5)/2 = 3.5 km/h
Average speed = 2ab/(a+b)
= (2 x 4 x 6)/(4 + 6)
= 48/10
= 4.8 km/h
Average speed of entire journey
= (39 + 39 + 39)/(39/26 + 39/39 +39/52)
= 3/(1/26 + 1/39 +1/52)
= 3/[(6 + 4 + 3)/156]
= 3 x 156/13 = 36 km/h
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