Ratio of speed = 2 : 3
Ratio of times taken for same distance = 1/2 : 1/3
From question 1/2 : 1/3 = t : 36
? (1/3) x t = (1/2) x 36
? x = 54 min .
Let distance covered by boy is Y.
Then, 25 : 10 : : 1000 : Y
? Y = (10 x 1000)/25 = 400 m
Average speed = 2uv / (u + v)
= ( 2 x 35 x 45) / (35 + 45) km/hr.
= 39 3/8 km/hr
Length of two sides of square
= 8 x 1/2 km.
= 4 km.
? Area of the field = 2 x 2 sq. km
= 4 sq. km.
Speed in m/sec = speed in km/hr x (5 / 18 )
Speed in m/sec = ( 36 x 5/18 ) m/sec
= 10 m/sec
Speed in m/sec = speed in km/hr x (5 / 18 )
Speed in m/sec = ( 30.6 x 18 /5 ) m/sec
= 8.5 m/sec
Average speed = 2uv / ( u + v ) km/hr
=(2 x 64 x 80) / (64 + 80) km/hr
= (2 x 64 x 80) / 144 km/hr.
= 71.11 km/hr
At 3/4 of the usual speed, the time taken is 4/3 of the usual time
? 4/3 of usual time - usual time = 20 min
? 4x/3 - x = 20
? x/3 = 20
? x = 60 min.
speed of a train in kilometer per hour =45
Speed in meter per second = ( 5/18 ) x Speed in kilometer per hour
= 45 x 5/18
= 12.5 kmph
Speed of the motor car in meter per second = 250 / 25
= 10 m/s
Speed in km/hr = (18/5) x speed in m/s
= 10 x (18 / 5) km/hour
=36 km/hour.
W + R = 4 h 20 min
W + W = 5 h 20 min
? R + R = 3 h 20 min
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