Discussion
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- Question
- Suresh started cycling along the boundaries of a square field from corner point A. After half an hour, he reached the corner point C, diagonally opposite to A, if his speed was 8km/hr , what is the area of the field in square km.?
Options- A. 64
- B. 8
- C. 4
- D. Cannot be determined
- Correct Answer
- 4
ExplanationLength of two sides of square
= 8 x 1/2 km.
= 4 km.
? Area of the field = 2 x 2 sq. km
= 4 sq. km. - 1. A speed of 36 km/hr. is the same as?
Options- A. 10 m/sec.
- B. 7.2 m/sec.
- C. 2 m/sec.
- D. 129.6 m/sec. Discuss
- 2. A speed of 30.6 km/hr. is the same as?
Options- A. 5.1 m/sec.
- B. 8.5 m/sec.
- C. 110.16 m/sec.
- D. 1.7 m/sec. Discuss
- 3. A speed of 55 m / sec. is the same as?
Options- A. 198 km/hr.
- B. 11 km/hr.
- C. 15 5/18 km/hr.
- D. 275 km/hr. Discuss
- 4. A speed of 22.5 m/sec. is the same as?
Options- A. 40.5 km/hr.
- B. 81 km/hr.
- C. 36.8 km/hr .
- D. 72 km/hr. Discuss
- 5. A and B are two towns. Mr. Faruqui covers the distance from A to B on cycle at 16 km/hr. however, he cover the distance from B to A on foot at 9 km/hr. his average speed during the whole journey is?
Options- A. 12.5 km/hr.
- B. 10.25 km/hr.
- C. 11.52 km/hr.
- D. 12.32 km/hr. Discuss
- 6. A man goes uphill with an average speed of 35 km/hr, and covers down with an average speed of 45 km/hr. The distance travelled in both the cases being the same , the average speed for the entire journey is?
Options- A. 38 3/8 km/hr.
- B. 39 3/8 km/hr.
- C. 40 km/hr
- D. None of these Discuss
- 7. If a boy takes as much time in running 10 m as a car takes in covering 25 m, the distance covered by the boy during the time the car covers 1 km, is?
Options- A. 400 m.
- B. 40 m.
- C. 250 m.
- D. 650 m. Discuss
- 8. The ratio between the rates of walking of A and B is 2:3 , if the time taken by B to cover a certain distance is 36 minutes, the time taken by A to cover that much distance is?
Options- A. 24 min
- B. 54min
- C. 48 min
- D. 21.6min Discuss
- 9. A man, on tour travel first 160 km. at 64 km/hr. and the next 160 km. at 80 km/hr. The average speed for first 320 km. of the tour is?
Options- A. 35.55 km/hr
- B. 71.11 km/hr
- C. 36 km/hr
- D. 72 km/hr Discuss
- 10. By walking at 3/4 of his usual speed , a man reaches his office 20 minutes later than usual . this usual time is?
Options- A. 30 minutes
- B. 60 minutes
- C. 75 minutes
- D. 1 hour 30 minutes Discuss
Time and Distance problems
Search Results
Correct Answer: 10 m/sec.
Explanation:
Speed in m/sec = speed in km/hr x (5 / 18 )
Speed in m/sec = ( 36 x 5/18 ) m/sec
= 10 m/sec
Correct Answer: 8.5 m/sec.
Explanation:
Speed in m/sec = speed in km/hr x (5 / 18 )
Speed in m/sec = ( 30.6 x 18 /5 ) m/sec
= 8.5 m/sec
Correct Answer: 198 km/hr.
Explanation:
Speed in km/hr = speed in m/sec x (18 / 5 )
Speed in km/hr = ( 55 x 18 /5 ) km/hr
= 198 km/hr.
Correct Answer: 81 km/hr.
Explanation:
Speed in km/hr = speed in m/sec x (18 / 5 )
Speed in km/hr = (22.5 x 18 /5 ) km/hr
= 81 km/hr.
Correct Answer: 11.52 km/hr.
Explanation:
Average Speed = Total distance / time
= 2d / [( d / 16) + ( d / 9)]
= ( 2 x 16 x 9 ) / ( 16 + 9 ).
= 11.52 km/hr.
Shortcut :
Average speed = 2uv / (u + v)
= ( 2 x 16 x 9 ) / ( 16 + 9 )
= 11.52
Correct Answer: 39 3/8 km/hr.
Explanation:
Average speed = 2uv / (u + v)
= ( 2 x 35 x 45) / (35 + 45) km/hr.
= 39 3/8 km/hr
Correct Answer: 400 m.
Explanation:
Let distance covered by boy is Y.
Then, 25 : 10 : : 1000 : Y
? Y = (10 x 1000)/25 = 400 m
Correct Answer: 54min
Explanation:
Ratio of speed = 2 : 3
Ratio of times taken for same distance = 1/2 : 1/3
From question 1/2 : 1/3 = t : 36
? (1/3) x t = (1/2) x 36
? x = 54 min .
Correct Answer: 71.11 km/hr
Explanation:
Average speed = 2uv / ( u + v ) km/hr
=(2 x 64 x 80) / (64 + 80) km/hr
= (2 x 64 x 80) / 144 km/hr.
= 71.11 km/hr
Correct Answer: 60 minutes
Explanation:
At 3/4 of the usual speed, the time taken is 4/3 of the usual time
? 4/3 of usual time - usual time = 20 min
? 4x/3 - x = 20
? x/3 = 20
? x = 60 min.
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