Let the total journey be x km. then,
2x/15 + 9x/20 + 10 = x
? 8x + 27x + 600 = 60x
? x = 24
? Total journey = 24 km.
Let the total distance be y km.
Then, (y/2) x (1/60) + (y/2) x (1/50) = 44/3
? y/120 + y/100 = 44/3
? 5y + 6y = 8800
? y = 800
? Required distance = 800km.
Let the length of total journey be y km.
From question
( y/2 x 1/40 ) + ( y/2 x 1/60) = 8
? y/80 + y/120 = 8
? 3y + 2y = 1920
? y = 384 km.
Total time taken = (3/10 + 3/20 + 3/30 + 3/60) hrs.
= 3/5 hrs.
? Average speed = {12 / (3 / 5)} km/hr.
= (12 x 5 ) / 3 km/hr.
= 20 km/hr.
Let the distance be y km.
From question
y/3 - y/3.75 = 1/2
? (3.75y - 3y) / (3 x 3.75) = 1/2
? 1.5y= 3 x 3.75
? y = ( 3 x 3.75 ) / 1.5
= 7.5 km.
Due to stoppages, it covers 9 km. less per hour
Required time = Time taken to cover 9 km.
= 9 / ( 54 /60) min
= 10 min
Let total distance be y km.
Then , (2y / 3) / 4 + ( y / 3) / 5 = 42/60
? y/6 + y/ 15 = 7/10
? 5y + 2y = 21
? y = 3
? Required distance = 3 km.
Let The required distance be y km.
Then, y/3 + y/2 = 5
? 2y + 3y = 30
? y = 6 km
Distance = (4 x 11/4 )km.
= 11 km.
? Req. Time = 11km / (33/2) km/hr
= 2 x (11 / 33) hr.
=(2 / 3) x 60 minutes
= 40 minutes
Required time = (4 / 15) x 63 hrs.
= 16 hrs. 48 min
Speed in m/sec = ( 5 / 18 ) x Speed in kms/hr.
92.4 kms/hr = 92.4 x (5 / 18) m/sec.
? Req. distance = 92.4 x ( 5 / 18 ) x 600 meters
= 15400 m.
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