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- Question
- A plane flies along the four sides of a square field at a speed of 200, 400, 600 and 800 km/hr. Then find the average speed of plane around the square field.
Options- A. 394
- B. 400
- C. 414
- D. 384
- Correct Answer
- 384
ExplanationLet the side of the square field be x and the average speed of plane be y
x/200 + x/400 + x/600 + x/800 = 4x/y
? 25x/2400 = 4x/y
? y =384
? Average speed is 384 km/hr - 1. In how many minutes will Rohit cover a distance of 800 m, if he runs at speed of 10 km/hr?
Options- A. 5 min 12 sec
- B. 4 min 40 sec
- C. 5 min
- D. 4 min 48 sec Discuss
- 2. Arjun runs a distance of 1500 m in 5 minutes. What is his speed in Km/hr?
Options- A. 16 km/hr
- B. 18 km/hr
- C. 15 km/hr
- D. 20 km/hr Discuss
- 3. A and B are 20 km apart. A can walk at an average speed of 4 km/hr and B at 6 km/h. If they start walking towards each other at 7:000 am, when they will meet?
Options- A. 8:00 am
- B. 8:30 am
- C. 9:00 am
- D. 10:00 am Discuss
- 4. Pipe A fills the cistern in half an hour and pipe B in 40 minutes, but owing to a crack in the bottom of the cistern it is found that pipe A now takes, 40 minutes to fill the cistern. How long will B take now to fill it and how long will the crack take to empty it?
Options- A. The leak empties in 1 hour and B fills in 2 hours
- B. B fills in an hour and the leak empties in 2 hours
- C. B fills in an hour and the leak empties in an hour
- D. Data inadequate Discuss
- 5. A cistern can be filled by one of two pipes in 30 minutes and by the other in 36 minutes. Both pipes are opened together for a certain time but being particularly clogged only 5 / 6 of the full quantity of water flows through the former and only 9 / 10 through the later. The obstructions, however, being suddenly removed the cistern is filled in 15 1/ 2 minutes from that moment. How long was it before the full flow of water began?
Options- A. 1 minutes
- B. 2 minutes
- C. 21/2 minutes
- D. 11/2 minutes Discuss
- 6. Laxman has to cover a distance of 6 km in 45 minutes . If he cover one half of the distance in 2/3 rd time . what should be his speed to cover the remaining distance in the remaining time?
Options- A. 12 km/hr.
- B. 16 km/hr.
- C. 3 km/hr.
- D. 8 km/hr. Discuss
- 7. A train cover a distance in 50 minutes, if it runs at a speed of 48 km per hour on an average. The speed at which the train must run to reduce the time of journey to 40 minutes?
Options- A. 50 km/hr.
- B. 55 km/hr.
- C. 60 km/hr.
- D. 70 km/hr. Discuss
- 8. Excluding stoppages, the speed of a bus is 54 km/hr. and including stoppages it is 45 km/hr. for how many minutes does the bus stop per hour?
Options- A. 9
- B. 10
- C. 12
- D. 20 Discuss
- 9. Two men start together to walk to a certain destination, one at 3.75 km an hour and another at 3 km an hour. The former arrives half an hour before the latter, the distance is?
Options- A. 9.5 km.
- B. 8 km.
- C. 7.5 km.
- D. 6 km. Discuss
- 10. A car covers four successive three km stretches at speed of 10 km/hr, 20 km/hr, 30 km/hr and 60 km/hr. respectively. Its average speed over this distance is?
Options- A. 10 km/hr.
- B. 20 km/hr .
- C. 30 km/hr.
- D. 25 km/hr . Discuss
Time and Distance problems
Search Results
Correct Answer: 4 min 48 sec
Explanation:
Rohit's speed = 10 Km/hr = (10 x 5/18) m/sec = 50/18 m/sec
Time taken to cover 800 m = (800 / (50/18) ) sec
= (800 x 18/50) sec = 288 sec = 4 min 48 sec
Correct Answer: 18 km/hr
Explanation:
Speed = (1500/300 ) m/sec
= 5 m/sec
= (5 x 18/5 ) km/hr
= 18 km/hr
Correct Answer: 9:00 am
Explanation:
Suppose they will meet after T hours.
Distance = Speed x Time
Sum of distance traveled by them after T hours
6T + 4T = 20 km
T = 2 hours.
So they will meet at 7:00 AM + 2 hours = 9:00 AM
Correct Answer: B fills in an hour and the leak empties in 2 hours
Explanation:
Let the leak empties it in T hours
From the given rule, we have (T x 30) / (T - 30) = 40
? T = 120 minutes = 2 hours.
Now, from the question, applying the rule, we have time taken by B to fill the tank when crack in the bottom develops
= (120 x 40) / (120 - 40) = 60 minutes = 1 hour
Correct Answer: 1 minutes
Explanation:
Net filling in last 151/2 minutes
= 31/2 (1/30 + 1/36) = 341/360
Now, suppose they remained clogged for x minutes.
Net filling in these x minutes
= (x/30 x 5/6 + x/36 x 9/10) = 19 x/360
Remaining part = (1 - 19x/360) = (360 - 19x/360)
360 - 19x/360 = 341/360 or x = 1.
Hence, the pipes remained clogged for 1 minutes.
Correct Answer: 3 km/hr.
Explanation:
? Time left = (1/3 X 45/60) hr.
= 1/4 hr.
Distance left = 3km
? speed required = [3 / (1/4) ] km/hr.
= 3 x 4
=12km/hr .
Correct Answer: 60 km/hr.
Explanation:
Total Distance = 48 x (50/60) km.
= 40 km
Required speed = [40 / (40/60)] km.
= (40 x 60 )/ 40 km/hr.
= 60 km/hr.
Correct Answer: 10
Explanation:
Due to stoppages, it covers 9 km. less per hour
Required time = Time taken to cover 9 km.
= 9 / ( 54 /60) min
= 10 min
Correct Answer: 7.5 km.
Explanation:
Let the distance be y km.
From question
y/3 - y/3.75 = 1/2
? (3.75y - 3y) / (3 x 3.75) = 1/2
? 1.5y= 3 x 3.75
? y = ( 3 x 3.75 ) / 1.5
= 7.5 km.
Correct Answer: 20 km/hr .
Explanation:
Total time taken = (3/10 + 3/20 + 3/30 + 3/60) hrs.
= 3/5 hrs.
? Average speed = {12 / (3 / 5)} km/hr.
= (12 x 5 ) / 3 km/hr.
= 20 km/hr.
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