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  • Question
  • There are three taps of diameter 1 cm, 4/3 cm and 2 cm, respectively. The ratio of the water flowing through them is equal to the ratio of the square of their diameters. The biggest tap can fill the tank alone in 61 min. If all the taps are opened simultaneously, how long will the tank take to be filled?


  • Options
  • A. 44 min
  • B. 45 min
  • C. 155/18
  • D. None of the above

  • Correct Answer
  • None of the above 

    Explanation

    Time taken to fill the tank by the tap having 2 cm diameter = 61 min

    ? Time taken to fill the tank by the tap having 1 cm diameter
    = 61 x (2/1)2 = 244 min

    Similarly, time taken to fill the tank by the tap having 4/3 cm diameter
    = 61 x [(2 x 3)/4]2 = 61 x 9/4 = 549/4 min.

    ? Part of the tank filled by all the three pipes in 1 min
    = 1/61 + 1/244 + 1/(549/4)
    = (36 + 9 + 16)/2196 = 61/2196 = 1/36
    Hence, required time taken = 36 min


  • More questions

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    • Options
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    • 2. 
      The probability of getting a composite number when a six-faced unbiased die is tossed, is

    • Options
    • A. 1/4
    • B. 1/3
    • C. 1/2
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    • 3. 
      Ajay takes some loan from Rashmi at the rate of 5% per annum andd after 2 yr, Ajay gave back ? 8800 to Rashmi and this way paid his whole loan. Find the interest by Ajay.

    • Options
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    • 4. 582, 605, 588, 611, 634, 617, 600

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    • 5. 
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    • 6. 
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