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- Question
- If two function simultaneously, the reservoir will be filled in 12 hours. One pipe fills the reservoir 10 hours faster than the other. How many hours does the faster pipe take to fill the reservoir?
Options- A. 25 hours
- B. 28 hours
- C. 30 hours
- D. 35 hours
- Correct Answer
- 30 hours
ExplanationSuppose that one pipe takes N hours to fill the reservoir. Then another pipe takes (N - 10) hours.
? 1/N + 1/(N - 10) = 1/12
? 12(N - 10 + N) = N(N - 10)
or N2 - 34N + 120 = 0
or (N - 30)(N - 4) = 0
? N = 30 or N = 4
So, the faster pipe takes 30 hours to fill the reservoir. - 1. Three pipes A, B and C can fill a cistern in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill it in 7 hours. The time taken by C alone to fill the cistern is?
Options- A. 10 hours
- B. 12 hours
- C. 14 hours
- D. 16 hours Discuss
- 2. A tank is filled by a pipe A in 32 minutes and pipe B in 36 minutes. When full, it in can be emptied by a pipe C in 20 minutes. If all the three pipes are opened simultaneously, half of the tank will be filled in?
Options- A. 16 minutes
- B. 24 minutes
- C. 48 minutes
- D. None of these Discuss
- 3. Two taps can separately fill a cistern in 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
Options- A. 7 minutes
- B. 9 minutes
- C. 13 minutes
- D. 23 minutes Discuss
- 4. A cistern has two taps which fill it in 12 min. and 15 min. respectively. There is also a waste pipe in the cistern. When all the pipes are opened the empty cistern is full in 20 min. how long will the waste pipe take to empty a full cistern?
Options- A. 8 min.
- B. 10 min.
- C. 12 min.
- D. 16 min. Discuss
- 5. A tank be filled by one tap in 20 min. and by another in 25 min. Both the taps are kept open for 5 min. and then the second is turned off. In how many minutes more is the tank completely filled?
Options- A. 171/2 min.
- B. 12 min.
- C. 11 min.
- D. 6 min. Discuss
- 6. Two pipes A and B can fill a tank in 15 hours and 20 hours respectively while a third pipe C can empty the full tank in 25 hours. All the three pipes are opened in the beginning. After 10 hours, C is closed. The time taken to fill the tank is?
Options- A. 12 hours
- B. 131/2
- C. 16 hours
- D. 18 hours Discuss
- 7. A cistern which could be filled in 9 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full, in what time will the leak empty it?
Options- A. 80 hours
- B. 85 hours
- C. 90 hours
- D. 95 hours Discuss
- 8. A cistern has 3 pipes A, B and C, A and B can fill it in 2 and 3 hours respectively. C is a waste pipe. If all the 3 pipes be opened at once, 7/24 of the cistern will be filled up in 30 minutes. In what time can C empty the full cistern?
Options- A. 3 hours
- B. 4 hours
- C. 5 hours
- D. 6 hours Discuss
- 9. Two pipes, P ans Q can fill a cistern in 12 and 15 minutes respectively. Both are opened together, but at the end of 3 minutes the first is turned off. How much longer will the cistern take to fill?
Options- A. 81/4 minutes
- B. 11 1/4 minutes
- C. 73/4 minutes
- D. 83/4 minutes Discuss
- 10. Three pipes A, B and C can fill a cistern in 10 hours, 12 hours and 15 hours respectively. First A was opened. After 1 hour, B was opened and after 2 hours from the start of A, C also opened . Find the time in which the cistern is just full?
Options- A. 2 hrs.
- B. 4 hrs.
- C. 2 hrs. 52 min.
- D. 4 hrs. 52 min. Discuss
Pipes and Cistern problems
Search Results
Correct Answer: 14 hours
Explanation:
Part filled in 2 hours = 2 x 1/6 = 1/3
Remaining part = (1 - 1/3) = 2/3
(A + B)'s 7 hour's work = 2/3
? (A + B)'s 1 hour's work = (2/3 x 1/7) = 2/21
(A + B + C)'s 1 hour's work = 1/6
C's 1 hours work = (1/6 - 2/21) = 1/14
Hence, C alone can fill the cistern in 14 hours.
Correct Answer: None of these
Explanation:
Net filling in 1 min. = (1/32 + 1/36 - 1/20) = 13/1440
? Time taken to fill the tank = (1440/13) min.
Time taken to fill half of the tank = (1440/13) x 2 min. = (720/13) min.
= 555/13 min.
Correct Answer: 9 minutes
Explanation:
Work done by waste pipe in 1 min. = (1/10) + (1/15) - (1/18)
= (1/6) - (1/18) = 1/9
? Waste pipe can empty the cistern in 9 min.
Correct Answer: 10 min.
Explanation:
Work done by waste pipe in 1 min. = (1/12 + 1/15) - 1/20
= (3/20 - 1/20) = 1/10
? Waste pipe can empty the cistern in 10 min.
Correct Answer: 11 min.
Explanation:
Work done by both the taps in 5 min
= 5 (1/20 +1/25) = (5 x 9)/100 = 9/20
Remaining part = (1 - 9/20) = 11/20
Now, 1/20 part is filled in 1 min.
So, 11/20 part will be filled in 11 min.
Hence, the tank will be full in 11 more min.
Correct Answer: 12 hours
Explanation:
Part filled in 10 hours = 10 x (1/15 + 1/20 - 1/25) = 23/30
Remaining part = (1 - 23/30) = 7/30
Now, (1/15 + 1/20) part is filled by A and B in 1 hr.
7/30 part be filled them in (60/7) x (7/30) = 2 hrs.
? Total time taken to fill the tank = (10 + 2) hrs. = 12 hrs.
Correct Answer: 90 hours
Explanation:
Let the leak empty the full cistern in N hours
Now, applying the given rule (9 x N) / (N - 9) = 9 + 1
or N = 90 hours.
Correct Answer: 4 hours
Explanation:
? 7/24 of the cistern will be filled up in 1/2 hr.
? The whole of the cistern will be filled up in (1/2) x (24/7) = 12/7 hrs.
Let the pipe C be empty the whole cistern in h hours
Now, applying the given rule we have,
(2 x 3 x h) / (3 x h + 2 x h - 2 x 3) = 12/7
or 42h = 60h - 72
? h = 4 hours.
Correct Answer: 81/4 minutes
Explanation:
12(1 - t/25) = 3
? t = 45/4 = 111/4 minutes
? Required answer = 111/4 - 3
= 81/4 minutes
Correct Answer: 4 hrs. 52 min.
Explanation:
[(A's 1 hour work) + (A + B)'s 1 hour work]
= (1/10) + [(1/10) + (1/12)] = 17/60
Remaining part = 1 - (17/60) = 43/60
Now, (A + B + C)'s 1 hour work = (1/10) + (1/12) + (1/15) = 1/4
1/4 part is filled by 3 pipes in 1 hour.
43/60 part will be filled by them in 4 x (43/60) hrs. = 2 hours 52 min.
? Total time taken to fill the cistern = 4 hours 52 min.
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