Suppose that one pipe takes N hours to fill the reservoir. Then another pipe takes (N - 10) hours.
? 1/N + 1/(N - 10) = 1/12
? 12(N - 10 + N) = N(N - 10)
or N2 - 34N + 120 = 0
or (N - 30)(N - 4) = 0
? N = 30 or N = 4
So, the faster pipe takes 30 hours to fill the reservoir.
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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