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- Question
- A tap having diameter 'd' empty a tank in 40 min. How long another tap having diameter '2d' take to empty the same tank?
Options- A. 5 min
- B. 20 min
- C. 10 min
- D. 80 min
- Correct Answer
- 20 min
ExplanationArea of tap ? Work done by pipe.
When diameter is doubled, area will be four times. so, it will work four times faster.
Hence, required time taken to empty the tank = 40 x 1/4 = 10 min. - 1. Two pipes X and Y can fill a cistern in 6 and 7 min, respectively. Starting with pipe X, both the pipes are opened alternately, each for 1 min. In what time will they fill the cistern?
Options- A. 62/7 min
- B. 63/7 min
- C. 65/7 min
- D. 61/7 min Discuss
- 2. There are two inlets A and B connected to a tank. A and B can fill the tank in 16 h and 10 h, respectively. If both the pipes are opened alternately for 1 h, starting from A, then how much time will the tank take to filled?
Options- A. 131/4 h
- B. 116/8 h
- C. 122/5 h
- D. 121/4 h Discuss
- 3. Inlet A is four times faster than inlet B to fill a tank. If A alone can fill it in 15 min, how long will it take if both the pipes are opened together?
Options- A. 10 min
- B. 12 min
- C. 15 min
- D. 14 min Discuss
- 4. A tank has a leak which would empty it in 8 h. A tap is turned on which admits 3 L a min into the tank and it is now emptied in 12 h. How many litres does the tank hold?
Options- A. 4320 L
- B. 4000 L
- C. 2250 L
- D. 4120 L Discuss
- 5. Two taps A and B can fill a tank in 20 min and 30 min, respectively. An outlet pipe C can empty the full tank in 15 min. A, B and C are opened alternatively, each for 1 min. How long will the tank take to be filled?
Options- A. 105 min
- B. 120 min
- C. 167 min
- D. 185 min Discuss
- 6. Two pipes A and B can fill a tank in 24 and 32 min, respectively. If both the pipes are opened together, after how much time pipe B should be closed so that the tank is full in 9 min?
Options- A. 40 min
- B. 30 min
- C. 10 min
- D. 20 min Discuss
- 7. A pipe can fill a cistern in 12 min and another pipe can fill it in 15 min, but a third pipe can empty it in 6 min. The first two pipes are kept open 5 min in the beginning and then the third pipe is also opened.Time taken to empty the cistern is?
Options- A. 38 min
- B. 22 min
- C. 42 min
- D. 45 min Discuss
- 8. A tank be filled by one tap in 20 min. and by another in 25 min. Both the taps are kept open for 5 min. and then the second is turned off. In how many minutes more is the tank completely filled?
Options- A. 171/2 min.
- B. 12 min.
- C. 11 min.
- D. 6 min. Discuss
- 9. A cistern has two taps which fill it in 12 min. and 15 min. respectively. There is also a waste pipe in the cistern. When all the pipes are opened the empty cistern is full in 20 min. how long will the waste pipe take to empty a full cistern?
Options- A. 8 min.
- B. 10 min.
- C. 12 min.
- D. 16 min. Discuss
- 10. Two taps can separately fill a cistern in 10 minutes and 15 minutes respectively and when the waste pipe is open, they can together fill it in 18 minutes. The waste pipe can empty the full cistern in?
Options- A. 7 minutes
- B. 9 minutes
- C. 13 minutes
- D. 23 minutes Discuss
Pipes and Cistern problems
Search Results
Correct Answer: 63/7 min
Explanation:
Part filled by X in 1st min and Y in the 2nd min = ( 1/6 + 1/7) = 13/42
Part filled by ( X + Y ) working alternately in 6 min = 1/2 x 13/42 x 6 =13/14
? Remaining Part = ( 1- 13/14 ) = 1/14
Now, it is the turn of X, one-sixth part is filled in 1 min.
One-fourteenth part is filled in (6 x 1/14) min = 3/7
? Required time = ( 6 + 3/7 ) = 63/7 min
Correct Answer: 122/5 h
Explanation:
Part filled by A in 1 h = 1/16
Part fill by B in 1 h = 1/10
Part filled by ( A + B ) in 2 h = 1/16 + 1/10 = 13/80
? Part filled by ( A + B ) in 12 h = 6 x 13/80 = 78/80
? Remaining part = 1 - 78/80 = 2/80 = 1/40
Now, it is the turn of A
Time taken by A to fill 1/40 part of the tank = (1/40) x 16 = 2/5 h
? Total time taken ( 12 + 2/5) h = 122/5 h
Correct Answer: 12 min
Explanation:
Time taken by A to fill the tank, m = 15 min
? Time taken by B to fill the tank, n = 15 x 4 = 60
? Required time taken m x n/(m + n)
= (15 x 60)/(15 + 60) = (15 x 60)/75 = 12 min
Correct Answer: 4320 L
Explanation:
Work done by the inlet in 1 h = (1/8 - 1/24) = 1/24
Work done by the inlet in 1 min = 1/24 x 1/60 = 1/1440
? Volume of 1/1440 part = 3 L
? Volume of the whole = 3 x 1440 = 4320 L
Correct Answer: 167 min
Explanation:
Part of the tank filled by the taps A, B and C in 3 min = 1/20 + 1/30 - 1/15 = (3 + 2 - 4)/60 = 1/60
? Time taken to fill [ 1 - ( 1/20 + 1/30 )] or 55/60th part of the tank = 3 x 55 = 165 min
Remaining part of the tank = 1 - 55/60 = 5/60 = 1/12
Tap A fill 1/0 part in 1 min, then
Remaining part = 1/12 - 1/20 = (5 -3)/60 = 2/60 = 1/30
i.e, 1/30th part is filled by B in 1 min
Hence, required time to fill the whole tank = (165 + 1 +1 ) min = 167 min
Correct Answer: 20 min
Explanation:
Here, A = 24 min, B = 32, T = 9 min
? Required time = B(1 - T/A )
= 32 ( 1 - 9/24 )
= 32 x 15/24 = 20 min.
Correct Answer: 45 min
Explanation:
Let the number of minutes taken to empty the cistern be T min.
According to the questions,
T/6 - (T + 5)/12 - (T + 5)/15 = 0
? T/6 - T/12 - 5/12 - T/12 - T/12 - T/15 = 0
? T/6 - T/12 - T/15 = 5/12 + 5/15
? (10T - 5T - 4T)/ 60 = (25 + 20)/60
? T/60 = 45/60
? T = 45 min.
Correct Answer: 11 min.
Explanation:
Work done by both the taps in 5 min
= 5 (1/20 +1/25) = (5 x 9)/100 = 9/20
Remaining part = (1 - 9/20) = 11/20
Now, 1/20 part is filled in 1 min.
So, 11/20 part will be filled in 11 min.
Hence, the tank will be full in 11 more min.
Correct Answer: 10 min.
Explanation:
Work done by waste pipe in 1 min. = (1/12 + 1/15) - 1/20
= (3/20 - 1/20) = 1/10
? Waste pipe can empty the cistern in 10 min.
Correct Answer: 9 minutes
Explanation:
Work done by waste pipe in 1 min. = (1/10) + (1/15) - (1/18)
= (1/6) - (1/18) = 1/9
? Waste pipe can empty the cistern in 9 min.
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