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- Question
- An inlet pipe fills 1/8 part of a tank in 1 h. How much time will the pipe take to fill the empty tank?
Options- A. 4 h
- B. 2 h
- C. 6 h
- D. 8 h
- Correct Answer
- 8 h
ExplanationWe know that, when a pipe fills 1/m part of a tank in 1 h, then the pipe takes m h to fill the tank.
Here, 1/m = 1/8 ? m = 8
? Required time to fill the tank = 8 h - 1. A cistern is normally filled in 8 hrs. but takes 2 hrs. longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?
Options- A. 16 hrs.
- B. 40 hrs.
- C. 25 hrs.
- D. 20 hrs. Discuss
- 2. A pipe can empty a tank in 12 minutes and another pipe can empty it in 16 minutes. If both the pipes are opened simultaneously, find the time in which a full tank is emptied?
Options- A. 6 minutes
- B. 61/7 minutes
- C. 62/7 minutes
- D. None of these Discuss
- 3. A cistern is normally filled in 8 hours but takes two hours longer to fill because of a leak in its bottom. If the cistern is full, the leak will empty it in?
Options- A. 16 hrs.
- B. 20 hrs.
- C. 25 hrs.
- D. 40 hrs. Discuss
- 4. If a pipe fills a tank in 6 h, then what part of the tank will the pipe fill in 1 h?
Options- A. 1/3
- B. 1/6
- C. 1/4
- D. 1/5 Discuss
- 5. Pipe A can fill a tank in 45 hrs and pipe B can fill it in 36 hrs. If both the pipes are opened in the empty tank. In how many hours will it be full?
Options- A. 10 hr
- B. 15 hr
- C. 20 hr
- D. 28 hr Discuss
- 6. An outlet pipe can empty a cistern in 3 h. In what time will the pipe empty two-third part of the cistern?
Options- A. 4 h
- B. 2 h
- C. 3 h
- D. 5 h Discuss
- 7. A pipe can fill a tank in 20 h. Due to a leak in the bottom, it is filled in 40 h. If the tank is full, how much time will the leak take to empty it?
Options- A. 40 h
- B. 30 h
- C. 50 h
- D. 30 h Discuss
- 8. If a pipe fills a tank in 6 h, then what part of the tank will the pipe fill in 1 h?
Options- A. 1/3
- B. 1/6
- C. 1/4
- D. 1/5 Discuss
- 9. An outlet pipe can empty a cistern in 30 min, then what part of the cistern will it empty in 1 min?
Options- A. 1/20
- B. 1/15
- C. 1/30
- D. 1/18 Discuss
- 10. Three pipes A, B and C can fill a tank separately in 8 h,10 h and 20h, respectively. Find the time taken by all the three pipes to fill the tank when these pipes are opened together?
Options- A. 57/11 h
- B. 47/11 h
- C. 87/11 h
- D. 37/11 h Discuss
Pipes and Cistern problems
Search Results
Correct Answer: 40 hrs.
Explanation:
Here x = 8 hrs. and y = 8 + 2 = 10 hrs.
Now, applying the given rule, we have the
Required answer = (8 x 10) /(10 - 8) = 40 hrs.
Correct Answer: None of these
Explanation:
Required answer = (12 x 16) /(12 + 16) = 48 / 7 = 66/7 minutes.
Correct Answer: 40 hrs.
Explanation:
Work done by leak in 1 hour = (1/8 - 1/10) = 1/40
? The leak will empty the cistern in 40 hours.
Correct Answer: 1/6
Explanation:
We know that, when a pipe fills a tank in m h, then the part of tank filled in 1 h = 1/m
Here, m = 6
? Required part of the tank to be filled in 1h = 1/6 part
Correct Answer: 20 hr
Explanation:
Part filled A in 1 hr= (1/45)
Part filled B in 1 hr= (1/36)
Part filled by (A+B) together in 1 hr=(1/45)+(1/36)=1/20
So, The tank will be full in 20 hr.
Correct Answer: 2 h
Explanation:
Time taken by the pipe to empty the cistern = 3 h
Then, time taken by the pipe to empty the 2/3 part = 3 x 2/3 = 2 h
Correct Answer: 40 h
Explanation:
Let the leak empties the full tank in x h, then
Part emptied in 1 by leak = 1/x
Part filled by inlet in 1 h = 1/20
According to the question,
1/20 + 1/x = 1/40
? 1/x = 1/40 - 1/20 = 1- 2/40 = -1/40 [-ve sign Indicates emptying.]
Clearly, leak will empty the full tank in 40 h.
Correct Answer: 1/6
Explanation:
We know that, when a pipe fills a tank in m h, then the part of tank filled in 1 h = 1/m
Here, m = 6
? Required part of the tank to be filled in 1 h = 1/6 part
Correct Answer: 1/30
Explanation:
We know that, when a pipe empties a cistern in n min, then the part emptied by the pipe in 1 min = 1/n
Here, n=30
? Required part of the tank emptied in 1 min = 1/30 part
Correct Answer: 37/11 h
Explanation:
Part filled by A in 1 h = 1/8
Part filled by B in 1 h = 1/10
Part filled by C in 1 h = 1/20
Part filled by (A + B + C) in 1 h = 1/8 + 1/10 + 1/20
= (5 + 4 + 2)/40 = 11/40
? Required time to fill the tank = 40/11 h
= 37/11 h
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