? Work of (Ganesh, Ram and Sohan) for 1 day = 1/16
and work of Ganesh and Ram for 1 day = 1/24
? Work of Sohan for 1 day = 1/16 - 1/24 = 1/48
? Sohan alone will complete the work in = 1/(1/48) days = 48 days.
? In 10 days a work is complete by 15 men
? In 1 day a work is complete by = 15 x 10 = 150 men
? In 5 days the work is complete by = 20 boys
? 1 day the work is completed = 20 x 15 = 300 boys
? 150 men = 300 boys
or 1 men = 300/150 = 2 boys
10 men = 2 x 10 = 20 boys
10 men + 10 boys = 20 + 10 = 30 boys
? 20 boys complete the work in 15 days
? 30 boys complete the work in (15 x 20)/30 = 10 days
? No. of pages typed by the typist A in 4 hours = 100 x 4/10 = 40
? No. of remaining pages = 100 - 40 = 60
Let B and C worked for H hours
? (100 x H)/20 + (100 x H)/25 = 60
? 5H + 4H = 60
? H = 60/9 = 20/3 hours = 6 hours 40 min
? The time at which the report was typed 03.40 p.m.
? In 20 days the work is completed by = 16 men + 12 women
? In 1 day the work is completed by = 20 x (16 men + 12 women )
= 320 men + 240 women
In 40 days the work is complete by 18 women
? 1 day the work is complete by = 18 x 40 = 720 women
? 720 women = 320 men + 240 women
? (720 - 240)women = 320 men
? 480 women = 320 men
? 1 men = 480/320 = 3/2 women
? 12 men + 27 women = 12 x (3/2) + 27 = 45 women
? 18 women complete work in 40 days
? 45 women complete 1 work = 40 x 18/45 = 16 days
Efficiency is proportional to work done per day. Work done per day N number of days
= Amount of work done. Considering efficience of A and B initially as 1.
Let A alone can do the work in M days and B alone can do the same work in N days.
Then, 5/M + 5/N = Total work done = 1
Since efficiency of A and B are 2 and 1/3 respectively
? 6/M + 1/N = 1 ....(i)
and 1/M + 1/N = 5 .....(ii)
Now, subtracting equation (ii) from equation (i), we have M = 25/4 = 61/4 days.
(A + B)'s 20 day's work = (20 x 1/30) = 2/3
Remaining work = (1 - 2/3) = 1/3
1/3 work is done by A in 20 days
Whole work can be done by A in (3 x 20) days = 60 days.
( A + B) 's 1 days work = 1/8
B's 1 days work = 1/12
? A's 1 day's work = (1/8) - (1/12) = (3 - 2)/24 = 1/24
? A can complete the work in 24 days
Now, B's 4 days work = 4/12 = 1/3
Remaining work = 1 - 1/3 = 2/3
As, time taken by A to complete the work is 24 days.
? Time taken by A to do 2/3 of the work = 2/3 x 24 = 16 days
Ajay' s 1 days work = 1/25
Similarly, sanjay's 1 days work = 1/20
Ajays and Sanjay 's together 1 day's work
= (1/25) + (1/20) = (4 + 5)/100 = 9/100
Their 5 day's work together
= 5 x 1 day's work
= 5 x (9/100) = 45/100
Remaining work = 1 - (5/100) = 55/100
Now, this remaining work is done by Sanjay.
Let Sanjay takes N days to complete it.
Then, (1/20) x N = 55/100
? N = (55 x 20)/100
? N = 11 days
So, remaining work is done in 11 days by Sanjay.
(A + B)'s 2 day's work = 2 x (1/3) = 2/3
Remaining work = 1 - (2/3) = 1/3
A will complete 1/3 work in 2
A will complete 1 work in 6
A's 1 days work = 1/6
B's 1 day's work = (1/3) - (1/6) = 1/6
? B will take 6 days to complete the work alone.
Let B will take N days to complete the remaining job.
According to the question
(1/A) + (1/B) = 1/24 and 1/A = 1/32
? 1/B = (1/24) - (1/32) = 1/96
? B = 96 days
According to the question,
8[(1/A) + (1/B)] + N x (1/B) = 1
? 8 x (1/24) + (N/96) = 1
? (1/3) + (N/96) = 1
? N/96 = 1 -1/3
? N = (2 x 96)/3 = 64
Hence, B complete the remaining job in 64 days
Given, M1= 20, M2 = 25, T1 = 5, T2 = 10, D1 = 10 and D2 = ?
According to the formula,
M1T1D1= M2T2D2
? 20 x 5 x 10 = 25 x 10 x D2
? D2 = 20 x 5 x 10/25 x 10 = 4 days
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