A can do a piece of work in 12 days, B can do the same work in 8 days and c can do the same job in 4 / 5 th time required by both A and B. A and B work together for 3 days, then C complete days did C work?

25 men and 15 women can complete, a piece of work in 12 days.
? Work done by them in 8 days = 8/12 = 2/3
Remaining work is completed by 25 men in 6 days
? Time taken by 25 men to complete the whole work = 3 x 6 = 18 days

From the question
Time taken by 15 women to complete the whole work = 1 / (1/12 - 1/18)
= 1 / {(3 - 2) / 36} = 36/(3 - 2) = 36 days

Efficiency ( per minute) of Modi = 4 copies/min
Efficiency of Modi and Xerox together = 10 pages/min
? Efficiency of Xerox alone = 10 - 4 = 6 pages/min
? Mr. Xerox needs 6 min to copy 36 pages.

Y = 56 x (27/23) x (552/448)
=81

Extra men required =81-56
=25

A,s 1 days work =1/8
B's 1 day's work in breaking the building = 1/3
Now, according to the question,
A's 4 day's work = 4 x (1/8) = 1/2
Now, A's and B's 2 day's work
= 2[(1/8) - (1/3)] = 2 x (-5/24) = -10/24
Total work done in 6 days = 1/2 + (-10/24) = (12 - 10)/24 = 2/24 = 1/12
Remaining work = 1 - (1/12) = 11/12
Now, A has complete the work, so A can complete in N days.
(1/8) x N = 11/12
? N = (11 x 8) / 12
N = (11 x 2)/3 = 7¹/₃ days

(A + B)'s 2 day's work = (1/12) + (1/18) = 5/36
(A + B)'s 14 day's work = (5/36) x 7 = 35/36
Remaining work = 1 - (35/36) = 1/36

Now, it is the turn of A .
A's 1 day's work = 1/12
? 1/36 work is done by A in 12 x (1/36) days = 1/3 days
? Total time taken = 14¹/₃ days

Work of A for 1 day = 1/15
Work of B for 1 day = 1/20
Work of (A + B) together for 1 day = 1/15 + 1/20 = (4 + 3)/60 = 7/60
Remaining work after A alone does for 1 day = 1 - 1/15 = 14/15
? 7/60 part-work can be complete by (A + B) in 1 days
? 14/15 part-work can be completed by (A + B) in = (60/7) x (14/15) = 8 days.

(A + B)'s 5 day's work = 5 x (1/10 + 1/20) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/20 work is done by B in = 1 day
? 1/4 work is done by B in = 20 x (1/4) i.e., 5 days.

1 men's one day's work = 1/96
12 men's 3 day's work = 3 x (1/8) = 3/8
Remaining work = (1 - 3/8) = 5/8
15 men's 1 day's work = 15/96
Now, 15/96 work is done by them in 1 day
? 5/8 work will be done by them in = (96/15) x (5/ 8) i.e., 4 days

(B + C)'s 2 day's work = 2 x (1/10 + 1/15) = 1/3
Remaining work = (1 - 1/3) = 2/3
? 1/9 work is done by A in 1 day
? 2/3 work is done by A in (9 x 2) / 3 = 6 days

24 men complete the work in 16 days
? Work that 16 men complete in 12 days = (16/24) x (12/ 16) = 1/2 part of work in 12 days.

32 women complete the work in 24 days
? Work that 16 women complete in 14 days = (16/32) x (14/24) = 7/24 part of work in (12 + 2) = 14 days.

So, the remaining part of the work which done by (sixteen men + sixteen women) and required additional no. of men in 2 days = 1 - (1/2 + 7/24) = 1/2 - 7/24 = 5/24 (part)

Now, in 2 days 5/24 part part of the work is done by (24 x 16)/ 2 x (5/ 24) = 40 men
? Required additional no. of men = 40 - 16 =24.