B's 4 days work = (1/6) x 4 = 2/3
? Remaining work = 1 - (2/3) = 1/3
A's 1 day's work = 1/10
? 1/3 work is finished by A in
(10 x 1/3) = 31/3 days
A's and B,s 1 h work= 1/10
B's and C,s 1 h work = 1/15
and A's and C's 1 h work = 1/12
? A's B's and C's 1 h work
= (1/2) x [(1/10) + (1/15) + (1/12)] = (1/2) x (1/4) = 1/8
Hence B's work in 1 h = (1/8) - (1/12) = 1/24
? B independently can complete the work in 24 h.
Let the required days be x.
A works for (x - 2) days, while B work for x days.
According to the question
(x - 2)/10 + x/20 = 1
? 2x - 4 + x = 20
? 3x = 24
? x = 8 days
A's 1 day's work = 1/12
B's 1 day's work = 1/24
(A + B) 1 day's work = 1/12 + 1/24 days
= (2 + 1)/24 = 3/24 = 1/8
? (A + B)'s will finish the work in 8 days.
In 16 days the work is done by 24 men
? In 1 day the work is done by = (24 x 16) men
In 24 days the work is done by = 36 women
? In 1 day the work is done by = (36 x 24) women
? (16 x 24) men = 36 x 24 women
? 1 man = (36 x 24)/(16 x 24)
? 8 men = [(36 x 24)/(16 x 24)] x 8 =18 women
? 8 men + 6 women = (18 + 6) = 24 women
? 36 women do 1 work in 24 days
? 24 women do 1 work in 24 x 36 / 24 = 36 days
? In 12 days the work is done by = 24 boys
? In 1 day the work is done by = 24 x 12 = 288 boys
? In 9 days the work is done by = 16 men
? 1 day work is done by = 16 x 9 = 144 men
? 144 men = 288 boys
? 1 men = 288/144 = 2 boys
? 12 men + 12 boys = 12 x 2 + 12 = 36 boys
? 24 boys complete 1 work in 12 days
? 36 boys complete 1 work in (12 x 24)/36 = 8 days
Let the number of the men at the beginning = N
Given, M1 = N, M2 = N - 12, D1 = 18 and D2 = 30
According to the formula
M1D1 = M2D2
? N x 18 = (N - 12) x 30
? 3N = 5N - 60
? 2N = 60
? N = 30
Mason's 1 h work = 1/12
Mason's 6 h work = 6/12 = 1/2
Remaining work = 1 - (1/2) = 1/2
Remaining work can be finish in 5 h total work can be finished in 2 x 5 = 10 h.
(1/12) + (1/B) = (1/10)
? 1/B = (1/10) - (1/12) = 1/60
Boy can complete the work in 60 h.
Time take by A to complete a work = N days
? Time taken by B to complete the same work = 2N days
According to the question,
(1/N) + (1/2N) = 1/12
? 3 / 2N = 1/12
? N = (3 x 12)/2 = 18
Time taken by B to complete the same work = 2N= 2 x 18 = 36 days
Let A takes x and B takes 3N days to finish the job.
According to the question,
3N - N = 30
? N = 30/2 = 15 days
? B's time to complete the work = 3N
= 3 x 15 = 45 days
? (A + B)'s 1 day's work
= (1/15) + (1/45) = (3 + 1)/45 = 4/45
? (A + B) will finish the work in 4/45 days
? Required time = 4/45 = 111/4
Work done by (x + y + z) in 1 day
= 50% = 1/2
Work done by x in 1 days = 20% = 1/5
Work done by y in 1 days = 25% = 1/4
? Work done by z in 1 day
= (1/2) - (1/5) - (1/4)
= (10 - 4 - 5)/20
= 1/20 = 5%
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.