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- Question
- A can do a piece of the work in 10 days and B in 20 days. They begin together but A leaves 2 days before the completion of the work. The whole work will be done in?
Options- A. 8 days
- B. 7 2/3 days
- C. 7 days
- D. 6 days
- Correct Answer
- 8 days
ExplanationLet the required days be x.
A works for (x - 2) days, while B work for x days.
According to the question
(x - 2)/10 + x/20 = 1
? 2x - 4 + x = 20
? 3x = 24
? x = 8 days - 1. A alone can complete a work in 12 days and B alone can complete the same work in 24 days. In how many days can A and B together complete the same work?
Options- A. 6 days
- B. 4 days
- C. 10 days
- D. 8 days Discuss
- 2. 24 men can do a work in 16 days while 36 women can do the same work in 24 days. In how many days will 8 men and 6 women together complete the same work?
Options- A. 36 days
- B. 28 days
- C. 32 days
- D. 24 days Discuss
- 3. 24 boys can complete a work in 12 days while 16 men can complete the same work in 9 days. In How many days will 12 boys and 12 men together complete the same work?
Options- A. 6 days
- B. 8 days
- C. 7 days
- D. 10 days Discuss
- 4. 14 workers can make 1400 toys in 5 days. One day after they started the work 14 more workers joined them. How many days will they take to complete the remaining work?
Options- A. 2 days
- B. 3 days
- C. 4 days
- D. 31/2 Discuss
- 5. A is twice as good a workman as B and together they finish a piece of work in 14 days. A alone can finish the work in?
Options- A. 11 days
- B. 21 days
- C. 28 days
- D. 42 days Discuss
- 6. A and B can do a piece of work in 10 h. B and C do it in 15 h, while A and C take 12 h to complete the work. B independently can complete the work in
Options- A. 12 h
- B. 16 h
- C. 20 h
- D. 24 h Discuss
- 7. A can do a piece of work in 10 days, while B can do it in 6 days. B worked at it for 4 days. How long will A take to finish the remaining work?
Options- A. 31/3 days
- B. 32/3 days
- C. 32/5 days
- D. 35/7 Discuss
- 8. A contractor undertook to do a certain piece of the work in 18 days. He employed certain number of men but 12 of them being absent from the very 1st day, the rest could finish the work in 30 days . Find the number of men originally employed.
Options- A. 40
- B. 15
- C. 45
- D. 30 Discuss
- 9. A mason can build a tank in 12 h. After working for 6 h. he took the help of a boy and finished the work in another 5 h. The time that the boy will take alone to complete the work is?
Options- A. 30 h
- B. 45 h
- C. 60 h
- D. 64 h Discuss
- 10. A and B can do a job together in 12 days. A is 2 time as efficient as B. In how many days can B alone complete the work?
Options- A. 36
- B. 12
- C. 18
- D. 9 Discuss
Time and Work problems
Search Results
Correct Answer: 8 days
Explanation:
A's 1 day's work = 1/12
B's 1 day's work = 1/24
(A + B) 1 day's work = 1/12 + 1/24 days
= (2 + 1)/24 = 3/24 = 1/8
? (A + B)'s will finish the work in 8 days.
Correct Answer: 36 days
Explanation:
In 16 days the work is done by 24 men
? In 1 day the work is done by = (24 x 16) men
In 24 days the work is done by = 36 women
? In 1 day the work is done by = (36 x 24) women
? (16 x 24) men = 36 x 24 women
? 1 man = (36 x 24)/(16 x 24)
? 8 men = [(36 x 24)/(16 x 24)] x 8 =18 women
? 8 men + 6 women = (18 + 6) = 24 women
? 36 women do 1 work in 24 days
? 24 women do 1 work in 24 x 36 / 24 = 36 days
Correct Answer: 8 days
Explanation:
? In 12 days the work is done by = 24 boys
? In 1 day the work is done by = 24 x 12 = 288 boys
? In 9 days the work is done by = 16 men
? 1 day work is done by = 16 x 9 = 144 men
? 144 men = 288 boys
? 1 men = 288/144 = 2 boys
? 12 men + 12 boys = 12 x 2 + 12 = 36 boys
? 24 boys complete 1 work in 12 days
? 36 boys complete 1 work in (12 x 24)/36 = 8 days
Correct Answer: 2 days
Explanation:
? In 5 days 14 workers make = 1400 toys.
? In 1 days 14 workers make toys = 1400/5 = 280 toys.
Number of remaining toys = 1400 - 280 = 1120
and number of total workers = 14 + 14 = 28
? 14 workers make 1400 toys in 5 days.
? 28 workers make 1120 toys = (5 x 14 x 1120)/(28 x 1400) = 2 days
Correct Answer: 21 days
Explanation:
(A's 1 day's work) : (B's 1 day's work) = 2 : 1
Now, ? (A + B)'s day's work = 1/14
? A's 1 day's work = (1/14) x 2/3 = 1/21
? A alone can finish the work in 21 days.
[Dividing 1/14 in the ratio 2 : 1 ]
Correct Answer: 24 h
Explanation:
A's and B,s 1 h work= 1/10
B's and C,s 1 h work = 1/15
and A's and C's 1 h work = 1/12
? A's B's and C's 1 h work
= (1/2) x [(1/10) + (1/15) + (1/12)] = (1/2) x (1/4) = 1/8
Hence B's work in 1 h = (1/8) - (1/12) = 1/24
? B independently can complete the work in 24 h.
Correct Answer: 31/3 days
Explanation:
B's 4 days work = (1/6) x 4 = 2/3
? Remaining work = 1 - (2/3) = 1/3
A's 1 day's work = 1/10
? 1/3 work is finished by A in
(10 x 1/3) = 31/3 days
Correct Answer: 30
Explanation:
Let the number of the men at the beginning = N
Given, M1 = N, M2 = N - 12, D1 = 18 and D2 = 30
According to the formula
M1D1 = M2D2
? N x 18 = (N - 12) x 30
? 3N = 5N - 60
? 2N = 60
? N = 30
Correct Answer: 60 h
Explanation:
Mason's 1 h work = 1/12
Mason's 6 h work = 6/12 = 1/2
Remaining work = 1 - (1/2) = 1/2
Remaining work can be finish in 5 h total work can be finished in 2 x 5 = 10 h.
(1/12) + (1/B) = (1/10)
? 1/B = (1/10) - (1/12) = 1/60
Boy can complete the work in 60 h.
Correct Answer: 36
Explanation:
Time take by A to complete a work = N days
? Time taken by B to complete the same work = 2N days
According to the question,
(1/N) + (1/2N) = 1/12
? 3 / 2N = 1/12
? N = (3 x 12)/2 = 18
Time taken by B to complete the same work = 2N= 2 x 18 = 36 days
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