? C's 1 day's work
= [( A + B + C)'s 1 day's work] - [(A + B)'s 1 day's work]
= [1/8 - (1/24 + 1/16)] = (1/8 - 5/48) = 1/48
? C alone can do it in 48 days.
? (1/5 + 1/9 + 1/15) = 17/45 work is finished in 1 hour
? Remaining work = 1 - 17/45 = 28/45
? (A + B)'s 1 hour's work = 1/5 + 1/9 = 14/45
14/45 work is done by (A and B) in 1 hour
28/45 work will be done by A and B in (45/14) x (28/45) = 2 hours
25 men reap the field in 20 days
? 10 men can reap the feild in (20 x 25)/ 10 = 50 days.
When 15 men leave the work, 10 men remain and they can reap in 371/2 days
= (371/2)/ 50 = 3/4 of the field
Hence, all men must work till (1 - 3/4) = 1/4 of the field is reaped in 20/4 = 5 days.
(A + B )'s 1 day ' s work = 1/72
(B + c)'s 1 day' s work = 1/120
(A + C)'s 1 day's work = 1/90
2(A + B + C)'s 1 days work = 1/72 + 1/120 + 1/90
? ( A + B + C )'s 1 day's work (5 + 3 + 4)/(360 x 2) = 12/(360 x 2) = 1/60
? A's 1 day's work = (A + B + C) 's 1 day's work - (B + C)'s 1 day's work
= 1/60 - 1/120 = (2 - 1)/120 = 1/120
? A alone can finish the work in 120 days.
(A+ B )' s 1 day ' s work = 1/18
(B +C )'s 1 day ' s work = 1/24
(C + A) 's 1 day 's work = 1/36
From Eqs. (i), (ii) and (iii), we get
2(A + B + C)' s 1 day 's work = 1/18 + 1/24 + 1/36
(A + B + C)'s 1 day's work = (4 + 3 + 2)/(72 x 2)
= 9/(72 x 2) = 1/16
? (A + B + C) can complete the work in 16 days
3 men = 4 women
? 1 man = 4/3 women
? 7 men + 5 women = 7 x (4/3) + 5 = 43/3 women
? M1D1W2 = M2D2W1
? 4 x 43 x 1 = (43/3) x D2 x 1
? D2 = 3 x 4 = 12 days
1 day work of A = 1/10 = 0.1
1 day work of B = 1/10 + 60% of 1/10 = 0.1 + 0.06 = 0.16
So number of days taken by B to complete the work = 1/0.16
= 62/3
? B's daily earning = Rs. (150 - 94) = Rs. 56
? A's daily earning = Rs. (150 - 76) = Rs. 74
? C's daily earning = Rs. [(150 - (56 + 74)] = Rs. 20
Since a alone can finish a work in 10 days and B alone can do it in 15 days. So if they work together then the ration of work done by A and B is = (1/10) : (1/15).
? The wages A will get = (1/10)[(1/10) + (1/15)] x 75
= Rs. 45
? Factory A turns out x cars in one hour. Factory B turns out y/2 cars in one hour.
? In one hour both the factories A and B can turn out (x + y/2) cars
? In 8 hours both factories turn out = 8( x + y/2) cars
= 4(2x + y) cars.
(A's 1 day's work) : (B's 1 day's work) = 2 : 1
Now, ? (A + B)'s day's work = 1/14
? A's 1 day's work = (1/14) x 2/3 = 1/21
? A alone can finish the work in 21 days.
[Dividing 1/14 in the ratio 2 : 1 ]
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