(A + B )'s 1 day ' s work = 1/72
(B + c)'s 1 day' s work = 1/120
(A + C)'s 1 day's work = 1/90
2(A + B + C)'s 1 days work = 1/72 + 1/120 + 1/90
? ( A + B + C )'s 1 day's work (5 + 3 + 4)/(360 x 2) = 12/(360 x 2) = 1/60
? A's 1 day's work = (A + B + C) 's 1 day's work - (B + C)'s 1 day's work
= 1/60 - 1/120 = (2 - 1)/120 = 1/120
? A alone can finish the work in 120 days.
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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