Given, M1 = 20 D1 = 7, M2 = 20 + 8 = 28
and D2 = ?
Using formula, M1D1 = M2D2
? 20 x 7 = 28 x D2
? D2 = (20 x 7)/28 = 5 days
Here A = 60 days, B = 75 days, D = 30, T = ?
? Required time = (B - D) x [A/(A + B)]
= (75 - 30) x [60/(60 + 75)]
= (45 x 60)/135 = 20 days
? Required time = 20 days
(P + Q)'s 10 day's work= (1/30) x 10 = 1/3
Remaining work = (1 -1/3) = 2/3
2/3 work is done by P in 20 days.
? Whole work is done by P in 20 x (3/2) = 30 days
Time taken to complete the work by X =10 x 4 = 40 = 40 days
Time taken to complete the work by Y = (40 x 100)/40 = 100 days
Time taken to complete the work by Z = 13 x 3 = 39 days
Hence, Z will complete the work first.
According to the formula,
Required time = ?ab
Where a = 25 and b = 49
? Require time = ?25 x 49 = 5 x 7
= 35 days
1 man = 2 woman = 3 boys
? 1 man + 1 woman + 1 boy = (3 + 3/2 + 1) boys = 11/2 boys
Here M1 = 3 M2 = 11/2, D1 = 88 and D2 = ?
According to the formula
M1D1 = M2D2
? D2 = M1D1/M2
? Required number of days
= 3 x 2 x 88/11 = 3 x 2 x 8 = 48 days
Given, M1 = 12, M2 = 8 , D1 = 24 , W1 = 1, W2 = 1
According to the formula,
M1D1W2 = M2D2W1
? 12 x 24 x 1= 8 x D2 x 1
? D2 = (12 x 24)/8
= 12 x 3 = 36 days
Given, M1 = 20, T1 = 4, W1 = 30,
M2 = 20 - 4 = 16, T2 = 12 and W2 = ?
According to the formula,
M1T1W2 = M2T2W1
? 20 x 4 x W2 = 16 x 12 x 30
? W2 = (16 x 12 x 30)/(20 x 4) = 12 x 6 = 72 trees
Given, M1 = 40, W1 = 200, T1 = 8, D1 = 12,
M2 = 30, W2 = 300, T2 = 6 and D2 = ?
Then, using formula
M1T1D1W2 = M2T2D2W1
? 40 x 8 x 12 x 300 = 30 x 6 x D2 x 200
? D2 = (40 x 8 x 12 x 300)/(30 x 6 x 200) = 32 days.
Let the required number of units of work = k
According to the formula,
W1= m and W2 = k
M1T1D1W2 = M2T2D2W1
? m x m x m x k = n x n x n x m
? x= (m x n3) / m3 = n3/m2
Given, M1 = 20.
M2 = 20 + k
W1 = 1/3, W2 = 1 - 1/3 = 2/3
D1 = 20 and D2 = 25
According to the formula,
M1D1W2 = M2D2W1
? 20 x 20 x (2/3) = (20 + k) x 25 x 1/3
? 20 x 20 x (2/3) = (20 + k) x 25/3
? 16 x 2 = 20 + k
? k = 32 - 20 = 12
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