Discussion
Home ‣ Aptitude ‣ Time and Work Comments
- Question
- When A alone does a piece of work, he takes 25 days more than the time taken by (A + B) to complete that particular work, while B alone takes 49 days more than the time taken by (A + B) to finish the same work . A and B together will take what time for finish this work?
Options- A. 35 days
- B. 25 days
- C. 15 days
- D. 45 days
- Correct Answer
- 35 days
ExplanationAccording to the formula,
Required time = ?ab
Where a = 25 and b = 49
? Require time = ?25 x 49 = 5 x 7
= 35 days
- 1. If one man or two woman or three boys can finish a work in 88 days , then how many days will one man one woman and one boys together take to finish the same work?
Options- A. 46 boys
- B. 54 days
- C. 48 days
- D. 44 days Discuss
- 2. 'A' can do a piece of work in 2 hours, 'B' can do thrice the work in 8 hours and 'C' can do the same work as 'A' in 8 hours. If all of them work together, how long it would take them to complete the work?
Options- A. 1 hour
- B. 2 hour
- C. 3 hour
- D. 4 hours Discuss
- 3. 12 men and 16 boys can do a piece of work in 5 days while 13 men and 24 boys finish it in 4 days. 5 men and 10 boys will finish it in?
Options- A. 10 days
- B. 12 days
- C. 9 days
- D. 15 days Discuss
- 4. Ram finishes a work in 7 days. Rahim finish the same job in 8 days and Robert in 6 days. They take turns to finish the work. Ram worked on the first day, Rahim on the second day and Robert on the third and then again Ram and so on. Who was working on the last day when work got finished?
Options- A. Ram
- B. Rahim
- C. Robert
- D. Rahim and Robert Discuss
- 5. A and B can do a piece of work in 72 days, B and C can do it in 120 days, A and C can do it in 90 days. In what time can A alone do it?
Options- A. 60 days
- B. 90 days
- C. 115 days
- D. 120 days Discuss
- 6. X can do 1/4 of work in 10 days, Y can do 40% of the same work in 40 days and Z can do 1/3 of the work in 13 days. Who will complete the work first?
Options- A. X
- B. Y
- C. Z
- D. Both X and Z Discuss
- 7. P and Q can finish a work in 30 days, They work at it for 10 days and then Q left. The remaining work is done by P alone in 20 more days. How long will P take to finish the work alone?
Options- A. 30 days
- B. 20 days
- C. 60 days
- D. 50 days Discuss
- 8. A and B can do a piece of work in 60 days and 75 days, respectively. Both begin together but after a certain time A leaves off. In such case B finishes the remaining work in 30 days. After how many days did A leave?
Options- A. 25 days
- B. 21 days
- C. 20 days
- D. 24 days Discuss
- 9. 20 women can complete apiece of work in 7 day. If 8 more women are put on the job. In how many days will they complete the work?
Options- A. 4.5 days
- B. 5 days
- C. 5.5 days
- D. 4.5 days Discuss
- 10. 12 men can do a piece of work in 24 days. How many days are needed to go complete the work, if 8 men do this work?
Options- A. 28
- B. 36
- C. 48
- D. 52 Discuss
Time and Work problems
Search Results
Correct Answer: 48 days
Explanation:
1 man = 2 woman = 3 boys
? 1 man + 1 woman + 1 boy = (3 + 3/2 + 1) boys = 11/2 boys
Here M1 = 3 M2 = 11/2, D1 = 88 and D2 = ?
According to the formula
M1D1 = M2D2
? D2 = M1D1/M2
? Required number of days
= 3 x 2 x 88/11 = 3 x 2 x 8 = 48 days
Correct Answer: 1 hour
Explanation:
Efficiency of A = 50% [100/2]
Efficiency of B = 37.5% [100/(8/3)]
Efficiency of C = 12.5% [100/8]
Combined efficiency of A,B and C = 100%
So, they complete the work in 1 hour.
Correct Answer: 10 days
Explanation:
(12 men + 16 boys) can do a work in 5 days.
(60 men + 80 boys) can do a work in 1 day.
(13 men + 24 boys) can do a work in 4 days.
(52 men + 96 boys) can do a work in 1 day.
? 60 men + 80 boys = 52 men + 96 boys
8 men = 16 boys and 1 man = 2 boys
Now, 12 men + 16 boys = (12 x 2 + 16) boys
= 40 boys can do the work in 5 days
? 5 men + 10 boys = [5 x 2 + 10] boys
= 20 boys will take
= (40 x 5)/20 = 10 days
Correct Answer: Ram
Explanation:
Three day work or Ram, Rahim and Robert = 1/7 + 1/8 + 1/6
= (24 + 21 + 28)/168 = 73/168
Their six days work = (2 x 73)/168 = 146/168 = 73/84
Now, its Ram's turn to work on seventh day.
? 73/84 + 1/7 = 73 + 12/84 = 85/84 > 1
So, Ram will finish the work before the end of day.
Hence, Ram is working for the last day.
Correct Answer: 120 days
Explanation:
Combined efficiency of A and B = 1/72 ....(i)
Combined efficiency of B and C = 1/120 ....(ii)
Combined efficiency of A and C = 1/90 ....(iii)
On adding Eqs. (i), (ii) and (iii), we get
2(A + B + C) = 1/72 + 1/120 + 1/90 = (5 + 3 + 4)/360
= 12 / 360 = 1 / 30
? A + B + C = 1/60 .....(iv)
i.e Combined efficiency is 1/60 or we can say together A, B and C can complete the work in 60 days.
On subtracting Eq. (ii)from Eq. (iv), we get
Efficiency of A = Combined efficiency of A, B and C - Combined efficiency of B and C
= 1/60 - 1/120 = 1/120
Hence, A alone can do it in 120 days
Correct Answer: Z
Explanation:
Time taken to complete the work by X =10 x 4 = 40 = 40 days
Time taken to complete the work by Y = (40 x 100)/40 = 100 days
Time taken to complete the work by Z = 13 x 3 = 39 days
Hence, Z will complete the work first.
Correct Answer: 30 days
Explanation:
(P + Q)'s 10 day's work= (1/30) x 10 = 1/3
Remaining work = (1 -1/3) = 2/3
2/3 work is done by P in 20 days.
? Whole work is done by P in 20 x (3/2) = 30 days
Correct Answer: 20 days
Explanation:
Here A = 60 days, B = 75 days, D = 30, T = ?
? Required time = (B - D) x [A/(A + B)]
= (75 - 30) x [60/(60 + 75)]
= (45 x 60)/135 = 20 days
? Required time = 20 days
Correct Answer: 5 days
Explanation:
Given, M1 = 20 D1 = 7, M2 = 20 + 8 = 28
and D2 = ?
Using formula, M1D1 = M2D2
? 20 x 7 = 28 x D2
? D2 = (20 x 7)/28 = 5 days
Correct Answer: 36
Explanation:
Given, M1 = 12, M2 = 8 , D1 = 24 , W1 = 1, W2 = 1
According to the formula,
M1D1W2 = M2D2W1
? 12 x 24 x 1= 8 x D2 x 1
? D2 = (12 x 24)/8
= 12 x 3 = 36 days
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.