Three day work or Ram, Rahim and Robert = 1/7 + 1/8 + 1/6
= (24 + 21 + 28)/168 = 73/168
Their six days work = (2 x 73)/168 = 146/168 = 73/84
Now, its Ram's turn to work on seventh day.
? 73/84 + 1/7 = 73 + 12/84 = 85/84 > 1
So, Ram will finish the work before the end of day.
Hence, Ram is working for the last day.
Given the average age of couple and their son = 40
=> Sum of age (H +W +S) = 40×3
Let the age of daughter in law at the time of marriage = D years
Now after 10 years,
(H + S +W) + 3×12 + D +12 + 10 = 38×5
178 + D = 190
D = 190 -178 = 12 years
Let the price of kerosene be x and household
consumption be y.
Expenditure = xy
New cost of kerosene = 1.1x, let new household
consumption be z.
In order to not to increase expenditure,
xy = 1.1x * a
? a= 10y/ 11
? consumption should decrease by = 1/11 X 100 = 9.09%
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