The efficiency of Romil is twice that of Sanjay and he can finish a work in 4 h less than the time taken by Sanjay. If both of them work together they can finish the same work in?

8 h
3 h
8 / 3 h
4 / 3 h

Correct Answer: 8 / 3 h

Explanation:

As the efficience of Romil is twice that of Sanjay, Romil, will take x h for completeion of the work, when Sanjay is taking 2x h.
Given, 2x - x = 4
⇒ x = 4
Hence, they take = 1/(1/4 + 1/8) = 8/3 h

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