(P + Q)'S 1 day's work = 1/6
(Q + R)'s 1 day's work = 1/10
(P + R)'s 1 day's work = 1/5
On adding, 2 (P + Q + R)'s 1 day's work = 1/6 + 1/10 + 1/5 = 7/15
( P + Q + R)'s 1 day's work = 7/30
? (P + Q + R)'s can do the entire work in = 30/7 = 42/7 days
Women's 1 day's work = 1/6
(Women + Daughter)'s 1 day's work = 1/4
? Daughter's 1 day's work = 1/4 - 1/6 = 1/12
So, the daughter can do the work in 12 days.
(A + B + C)' S 1 day's work = (1/24) + (1/6) + (1/12) = 7/24
? (A + B + C) can do the entire work in = 24/7
= 33/7 days
Efficiency of (A + B) = 12.5%
Efficiency of (B + C) = 8.33%
Efficiency of (C + A) = 12.5%
? Efficiency of [(A + B) + (B + C) + (C + A)] = 33.33%
? Efficiency of (A + B + C) = 16.66%
? No. of days Required by A, B and C together = 100/16.66 = 6 days
Efficiency of (A + B) = 8.33%
Efficiency of (B + C) = 6.66%
Efficiency of (C + A) = 5.00%
? Efficiency of A + B + C = (8.33 + 6.66 + 5) / 2 = 10%
? Efficiency of C = Efficiency of [(A + B + C) - (A + B) ]
= (10 - 8.33) = 1.66%
? No. of days required by C alone = 100/1.66 = 60days
Efficiency of A + B = 33.33% = 100/3
Ratio of efficiency of A and B = 3 : 1
? Efficiency of A = (3/4) x 33.33 = 25%
? Number of days taken by A = 100/25 = 4
As the efficience of Romil is twice that of Sanjay, Romil, will take x h for completeion of the work, when Sanjay is taking 2x h.
Given, 2x - x = 4
? x = 4
Hence, they take = 1/(1/4 + 1/8) = 8/3 h
Number of regular hours during 4 weeks = 8 x 5 x 4 = 160
Amount paid for regular working hours = 160 x 5 = ? 800
Balance left = (920 - 800) = ? 120
So, ? 120 is paid for his over time at ? 8 per h.
? Total number of overtime working hours = 120/8 = 15 h
Total working hours = (160 + 15) = 175 h
Net part filed in 1 h = (1/20 + 1/30 - 1/40) = 7/120
Hence, the tank will be full in 120/7 = 171/7 h
Portion of work completed by one man in 11/2 days.
i.e., 3/2 days = 3/(2 x 3) = 1/2
Portion of work completed by one women in 11/2 days.
i.e., 3/2 days = 3/(2 x 4) = 3/8
? Portion of work completed by boys = 1 - (1/2 + 3/8) = 1/8
Now, portion of work completed by each boy in 3/2 days = 3/(2 x 12) = 1/8
Hence, only one boys would be required.
Efficiency of the leak = 1/6
Combined efficiency of leak and inlet pipe
So, efficiency of inlet pipe = 1/6 - 1/8 = (4 - 3)/24 = 1/24
Inlet pipe can fill the tank in 24 h, at rate of 4 L/min.
? Capacity = 24 x 60 x 4 = 5760 L
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