A's 10 day's work = (10 x 1/80) = 1/8
Remaining work = (1 - 1/8) = 7/8
? 7/8 work is done by B in 42 days
? Whole work will be done by B in (42 x 8/7) = i .e., 48 days.
? (A + B)'s day's work = (1/80 + 1/48) = 8/240 = 1/30
Hence, A and B together can finish it in 30 days.
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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