Given, M1 = 5, M2 = ?, T1 = 7, T2 = 3,
W1 = 35 and W2 = 65
According to the formula,
M1T1W2 = M2T2W1
? 5 x 7 x 65= M2 x 3 x 35
? M2 = (5 x 7 x 65)/(35 x 3) = 65/3 boys
Let food stock will be exhausted in x days .
Given, m1 = 120, D1 = 45
M2 = 120 + 30 = 150
and D2 = ?
Then, using M1D1 = M2D2
? 120 x 45 = 150 x D2
? D2 = 120 x 45/120 = 36
Given, M1 = 6, M2 = 8 , T1 = 16 h,
and T2 = ?, W1 = W2 = 1
According to the formula.
M1T1W2 = M2T2W1
? 6 x 16 x 1 = 8 x T2 x 1
? T2 = 16 x 6/8 = 2 x 6 = 12 h
Given, M1 = 10 D1 = 8, M2 = ? and D2 = 1/2
From M1D1 = M2D2
? 10 x 8 = M2 x 1/2
? M2 = 10 x 8 x 2
? M2 = 160
12 men =18 women
? 1 man = 18/12 women
? 8 men = 18/12 x 8 = 12 women
Given m1 = 18 M2 = 12 +16 = 28,
D1 , D2 = ? and W1 = W2 = 1
According to the formula
M1D1W2 = M2D2W1
? 18 x14 x1= 28 x D2 x1
? D2 = (18 x 14)/28 = 9 days
Alen's one day's work =1/21
Border's one day's work = 1/42
Alen and Border's two days work(working alternatively) = (1/21) + (1/42) = 1/14
So, Alen and Border do 1/14 work in 2 days
So, they complete the work in 14 x 2 = 28 days.
M1 = 240, D1 = 48, M2 = 160 and D2 = ?
According to the formula,
M1D1 = M2D2
? 240 x 48 = 160 x D2
? D2= (240 x 48)/160 = 72
A 's 1 day's work = 1/4
B ' s 1 days's work = 1/12
(A+B) ' s day ' s work = 1/4 + 1/12
= (3 + 1)/12 = 4/12 = 1/3
Days required by A and B together to do the work = 1 / (A + B ) ' s day ' s work = 3 days
Let C alone can finish the job in T hours.
According to the question,
Work done by A, B and C in 1h = 1/2
? 1/6 +1/5 + 1/T = 1/2
? 1/T = 1/2 - 1/6- 1/5 = (15 - 5- 6)/30
? 1/T = 4/30 = 2/15
? T = 71/2 h
In 25 hours A can copy 75 pages
In 1 hour A can copy 75/25 = 3 pages
In 25 hours (A and B) can copy = 135/27 = 5 pages
? In 1 hour B can copy (5 - 3) = 2 pages
? B can copy 42 pages in 21 hours.
? Mohan moves the whole lawn in x hours.
? mohan moves in 2 hours = 2/x part of the lawn.
? Unmoved part = 1 - 2/x = (x - 2)/ x part
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