A's 1 day's work = 1/12
B's 1 day's work = 1/12 + 60% of 1/12 = 1/12 x 160/100 = 2/15
? B can do the work in 15/2 days = 71/2 days.
Required time taken to complete the work by both together = x y / x + y
(Here x = 8 and y = 4)
? Required time = (8 x 4)/(8 + 4) = 32/12 = 22/3 hours
Required time taken by B to complete the work = xy / x - y
[Here x = 12 and y = 8]
? required time = (12 x 8) / (12 - 8) = 96/4 = 24 days
B's 9 day's work = 9 x (1/12) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/4 work is done by A in = 20 x (1/4) = 5 days.
? 1/3 of work is done by A in 5 days.
? Whole work will be done by A in 15 days.
? 2/3 of work is done by B in 10 days.
Whole work will be done by B in 10 x (5/2) i.e., 25days
? (A + B)'s 1 day's work = (1/15 + 1/25) = 8/75
So, both together can finish it in 75/8 days, i.e., 93/8days.
(A + B)'s 1 day's work = (1/30 + 1/40) = 7/120
? Time taken by both to finish the work = 120/7days = 171/7 days
Efficiency of A = 100/12 = 8.33%
Efficiency of B = 100/15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%
Number of days taken by A and B, when worked together = 100/15
= 62/3 days
One day's work of A and B = 1/14 + 1/21 = 5/42
? Required number of days = 42/5 = 8.4 days
Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%
? Number of days required by B = 100/6.66 = 15 days
One day's work of A and B = 1/x + 1/2x = 1/14
? x = 21
Since A is twice efficient as B so A will take half of the day taken by B.
Efficiency of Ajit : Bablu = 3 : 1
No. of days 1 : 3
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