A vessel contains mixture of liquids A and B in the ratio 3: 2. When 20 litres of the mixture is taken out and replaced by 20 litres of liquid B, the ratio changes to 1: 4. How many litres of liquid A was there initially present in the vessel?

Simple Interest in 1 year= Rs (1729 - 1586)
= Rs 143
now, SI in 2 year = Rs 286

Principal P= Rs(1586 - 286)
= 1300
And R= (100 × SI)/(P × T)
= (100 × 143)/(1300 × 1)
= 11 %
where, R = rate
SI= Simple Interest
P = Principal
T= Time

(21+ 99) x (30 - 19.02)
? (21+ 99 ) x (30 - 19)
? 120 x 11 = 1320

When A scores 75 points, B scores 50 points.
When A scores 90 points, C scores (90 - 18) = 72 points.
? When A scores 75 points, C scores = 72 × 75 / 90 = 60 points.
A : B : C = 75 : 50 : 60
C : B = 60 / 50 = 120 / 100
So, in a game of 120, C can give B
(120 - 100) = 20 points.

Average = sum of 6 numbers / 6
= ( 13 + 17 + 25 + 11 + 26 + 10 ) / 6
= 102 / 6
= 17

Here w = 2 litres per hour
? Required answer = {(15 x 10) / (15 - 10)} x 2 = 60 litres.

a + b + c = 11 x 3 = 33 .....(i)
c + d + e = 17 x 3 = 51 .....(ii)
e + f = 22 x 2 = 44 .....(iii)
e + c = 17 x 2 = 34 .....(iv)

From Eqs. (ii) and (iv), we get
34 + d = 51
? d = 17

Now adding Eqs. (i), (ii), (v), we get
a + b + c + d + e + f = 33 + 44 + 17 = 94
? Average of a, b, c, d, e and f = 94/6 = 15²?₃

Let (17.28 ÷ N ) / (3.6 x 0.2) = 2
Then, 17.28 / N = 1.44
? N = 17.28 / 1.44
= 12

? a + (1/b) = 1
ab + 1 = b ......(i)

Also, b + (1/c) = 1
? b = 1 - (1/c) ....(ii)

From Eqs. (i) and (ii), we get
ab + 1 = 1 - (1/c)
? ab = -1/c
? abc = -1