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- Question
- A petrol pump owner mixed leaded and unleaded petrol in such a way that the mixture contains 10 % unleaded petrol. What quantity of leaded petrol should be added to 1 liter mixtures, so that the percentage of unleaded petrol becomes 5 %?
Options- A. 1000 ml
- B. 900 ml
- C. 1900 ml
- D. 1800 ml
- Correct Answer
- 1000 ml
Explanation
- 1. A person bought 60 quintals of rice of two different sorts for Rs. 4642·50. The better sort costs Rs. 80 per quintal and the worse Rs. 75·50 per quintal. How many quintals were there of each sort?
Options- A. 25 quintals, 35 quintals
- B. 20 quintals, 40 quintals
- C. 32 quintals, 28 quintals
- D. None of these Discuss
- 2. In what proportion should water and wine at Rs. 22·50 a liter be mixed to reduce the price to Rs. 18 a liter?
Options- A. 1 : 4
- B. 4 : 1
- C. 2 : 3
- D. 3 : 2 Discuss
- 3. Two vessels A and B contains milk and water mixed in the ratio 5 : 3 and 2 : 3. When these mixtures are mixed to form a new mixture containing half milk and half water, they must be taken in the ratio ?
Options- A. 2 : 5
- B. 3 : 5
- C. 4 : 5
- D. 7 : 3 Discuss
- 4. The ratio of milk and water in 66 kg of adulterated milk is 5 : 1. Water is added to it to make the ratio 5 : 3. The quantity of water added is ?
Options- A. 22 kg
- B. 24·750 kg
- C. 16·500 kg
- D. 20 kg Discuss
- 5. In what proportion must wheat at Rs. 1·60 per kg be mixed with wheat at Rs. 1·45 per kg. So that the mixture be worth Rs. 1·54 per kg?
Options- A. 2 : 3
- B. 3 : 2
- C. 3 : 4
- D. 4 : 3 Discuss
- 6. In a mixture of 60 liters, the ratio of milk and water is 2 : 1. If the ratio of the milk and water is to be 1 : 2, then the amount of water to be further added is ?
Options- A. 20 litres
- B. 30 litres
- C. 40 litres
- D. 60 litres Discuss
- 7. 4 vessels of equal sizes contains mixture of spirit and water. The concentration of spirit in 4 vessels are 60 %, 70 %, 75 % and 80 % respectively. If all the 4 mixtures are mixed, find in the resultant mixture the ratio of spirit to water ?
Options- A. 57 : 13
- B. 23 : 57
- C. 57 : 23
- D. None of these Discuss
- 8. How much chicory at Rs. 24 a kg should be added to 15 kg of tea at Rs. 60 a kg as to make the mixture worth Rs. 39 a kg?
Options- A. 21 kg
- B. 20 kg
- C. 27 kg
- D. 18 kg Discuss
- 9. A mixture of 150 liters of Petrol and Diesel contains 20% Diesel. How much more Diesel should be added so that Diesel becomes 25% of the new mixture?
Options- A. 20 liter
- B. 5 liter
- C. 10 liter
- D. 35 liter Discuss
- 10. Two vessels A and B contain milk and water in the ratio 7 : 5 and 17 : 7 respectively. In what ratio mixtures from two vessels should be mixed to get a new mixture containing milk and water in the ratio 5 : 3?
Options- A. 1 : 2
- B. 2 : 1
- C. 2 : 3
- D. 3 : 2 Discuss
Alligation or Mixture problems
Search Results
Correct Answer: 25 quintals, 35 quintals
Explanation:
Correct Answer: 1 : 4
Explanation:
Correct Answer: 4 : 5
Explanation:
Correct Answer: 22 kg
Explanation:
Correct Answer: 3 : 2
Explanation:
Using the Alligation method ,
Here , C1 = 160 paise , C2 = 145 paise and Mean cost Price ( M ) = 154 paise
Required ratio = ( M - C2 ) : ( C1 - M )
? (Dearer wheat) : (Cheaper wheat) = 9 : 6
Hence , (Dearer wheat) : (Cheaper wheat) = 3 : 2
Correct Answer: 60 litres
Explanation:
Correct Answer: 57 : 23
Explanation:
Correct Answer: 21 kg
Explanation:
Correct Answer: 10 liter
Explanation:
Let us assume P liters of Diesel added to the mixture so that Diesel will be 25% in the new mixture.
According to Question,
Quantity of Diesel in 150 liters of the mixture = 20% of 150 = 150 x 20/100 = 30 liters.
After adding P liters of Diesel, The total quantity of Diesel becomes (30 + P) and total volume of mixture will be (150 + P).
Again According to Question,
After adding the P liters of Diesel in the mixture, the Diesel quantity becomes 25% of the new mixture.
Quantity of Diesel in new mixture = 25% of Total mixture.
? (30 + P) = (150 + P) x 25 %
? 30 + P = (150 + P) x 25/100
? 30 + P = (150 + P) x 1/4
? 120 + 4P = 150 + P
? 4P - P = 150 - 120
? 3P = 30
? P = 10 liters.
Correct Answer: 2 : 1
Explanation:
First of all we write the fraction of milk present in three mixtures. In A : 7 /12
In B : 17 /24
In combination of A and B : 5 /8
We now apply allegation rule on these fractions from figure.
So, Ratio of A: B = 2 : 1
2nd Method
Let us assume P mixture taken from first vessel and Q mixture taken from second vessel to form a new mixture.
Part of Milk in P mixture from first vessel = 7P/12
Part of Milk in Q mixture from Second vessel = 17Q/24
Part of Water in P mixture from first vessel = 5P/12
Part of Milk in Q mixture from Second vessel = 7Q/24
According to question,
After mixing the P and Q, we will get mixture.
Milk in New Mixture / Water in New Mixture = 5/3
{(7P/12) + (17Q/24 ) } /{ (5P/12) + (7Q/24) } = 5/3
{(14P + 17Q)/24 } /{ (10P + (7Q)/24 } = 5/3
{(14P + 17Q) } /{ (10P + (7Q)} = 5/3
(14P + 17Q) x 3 = 5 x (10P + (7Q)
42P + 51Q = 50P + 35Q
51Q - 35Q = 50P - 42P
8P = 16Q
P = 2Q
P/Q = 2
P : Q = 2 : 1
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