A shopkeeper buys 26 liter of milk @ Rs. 16 per liter. He also buys from another source an inferior quality of milk @ Rs. 10 per liter. How much quantity of the later should he buy to mix it with the former so that he can sell the mixture @ Rs. 14 per liter without making any loss?

The fruit content in both the fresh fruit and dry fruit is the same.

Given, fresh fruit has 68% water.so remaining 32% is fruit content. weight of fresh fruits is 100kg

Dry fruit has 20% water.so remaining 80% is fruit content.let weight if dry fruit be y kg.

Fruit % in freshfruit = Fruit% in dryfruit 

Therefore, (32/100) x 100 = (80/100 ) x y 

we get, y = 40 kg.

Let X be the event that cards are in a club which is not king and other is the king of club.
Let Y be the event that one is any club card and other is a non-club king.
Hence, required probability:
=P(A)+P(B)

= 12 C 1 * 1 C 1 52 C 2 + 13 C 1 * 3 C 1 52 C 2

= 12 * 2 52 * 51 + 13 * 3 * 2 52 * 51=  24 + 78 52 * 51 =  1 26

20% of a = b 

=> (20/100) * a = b 

 b% of 20 =(b/100) x 20 = [(20a/100)  / 100] x 20= 4a/100 = 4% of a.

Literally any percentage means divide by 100.

So 125 % = 125 100. That can be reduced to 5/4.

To convert to a decimal, you can do long division, dividing 5 into 4.

Given number of balls = 3 + 5 + 7 = 15

One ball is drawn randomly = 15C1

probability that it is either pink or red =  7 C 1 + 3 C 1 15 C 1 = 7 + 3 15 = 10 15 = 2 3

Let the cost price be x and selling price be y.
Loss = x ? y

When the cost price doubles, the loss gets tripled.
So it becomes like this, 2x ? y = 3(x-y)

=> x = 2y

Loss % = (loss/ C.P) x 100 = [(2y-y)/2y] x 100= 50 %

Purchase price = R s . 8748 1 - 10 100 3 = Rs. [8748 * (10/9) * (10/9 )* (10/9)] = Rs.12000