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  • Question
  • A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?


  • Options
  • A. 5:3
  • B. 1:4
  • C. 4:1
  • D. 9:1

  • Correct Answer
  • 9:1 

    Explanation

    According to question,
    Quantity of Milk/Quantity of Water = 3/2
    Let us assume the product ratio = n.
    Quantity of Milk = 3n and Quantity of Water = 2n liters
    Quantity of Milk + Quantity of Water = 20 liters
    3n + 2n = 20 liters
    5n = 20 liters
    n = 20/5
    n = 4
    Quantity of Milk = 3n liters
    Put the value of n,
    Quantity of Milk = 3 x 4 = 12 liters
    Quantity of Water = 2n
    Quantity of Water = 2 x 4 = 8 liters
    If 10 liters of mixture are removed first time, we will find how much milk and water contain in mixture.
    ? 20 liters of mixture contains 12 liter of milk.
    ? 1 liters of mixture contains 12/20 liter of milk.
    ? 10 liters of mixture contains 10 x 12/20 liter of milk.
    ? 10 liters of mixture contains 6 liter of milk.
    ? 10 liters of mixture contains 4 liter of water.
    If 10 liters of mixture are removed, then amount of milk removed = 6 liters and amount of water removed = 4 liters.
    Remaining milk = 12 - 6 = 6 liters
    Remaining water = 8 - 4 = 4 liters
    10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters and water = 4 liters.
    If the process is repeated one more time and 10 liters of the mixture are removed second time, then
    If 10 liters of mixture are removed, Again we will find how much milk and water contain in the mixture.
    ? 20 liters of mixture contains 16 liter of milk.
    ? 1 liters of mixture contains 16/20 liter of milk.
    ? 10 liters of mixture contains 10 x 16/20 liter of milk.
    ? 10 liters of mixture contains 8 liter of milk.
    ? 10 liters of mixture contains 2 liter of water.
    If 10 liters of mixture are removed, then amount of milk removed = 8 liters and amount of water removed = 2 liters.
    Remaining milk = (16 - 8) = 8 liters.
    Remaining water = (4 - 2) = 2 liters.
    Now 10 liters milk is added => total milk = 18 liters and water will be 2 liters.
    The required ratio of milk and water in the final mixture obtained
    Quantity of milk/Quantity of Water= 18:2 = 9:1

  • Tags: GATE, CAT, Bank Exams, AIEEE, Bank PO, Bank Clerk

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