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- Question
- A grocer buys two kind of rice at Rs. 1·80 and Rs. 1·20 per kg respectively. In what proportion should these be mixed, so that by selling the mixture at Rs. 1·75 per kg, 25 % may be gained?
Options- A. 2 : 1
- B. 3 : 2
- C. 3 : 4
- D. 1 : 2
- Correct Answer
- 1 : 2
Explanation
- 1. Kantilal mixes 80 kg of sugar worth of Rs. 6·75 per kg with 120 kg worth of Rs. 8 per kg. At what rate shall he sell the mixture to gain 20 %?
Options- A. Rs. 7·50
- B. Rs. 9
- C. Rs. 8·20
- D. Rs. 8·85 Discuss
- 2. Sugar at Rs. 15 per kg is mixed with sugar at Rs. 20 per kg in the ratio 2 : 3. Find the price per kg of the mixture?
Options- A. Rs. 18
- B. Rs. 16
- C. Rs. 17
- D. Rs. 19 Discuss
- 3. Some amount out of Rs. 7000 was lent at 6 % p.a. and the remaining at 4 % p. a. If the total simple interest from both the fractions in 5 years was Rs. 1600, the sum lent at 6 % p. a. was ?
Options- A. Rs. 2000
- B. Rs. 5000
- C. Rs. 3500
- D. None of these Discuss
- 4. A sum of Rs. 41 was divided among 50 boys and girls. Each boy gets 90 paise and a girl 65 paise. The number of boys is ?
Options- A. 16
- B. 34
- C. 14
- D. 36 Discuss
- 5. Rs. 675 was divided among 75 boys and girls. Each boy gets Rs. 20 whereas a girl gets Rs. 5. Find the number of boys and girls.
Options- A. 20 , 55
- B. 15 , 60
- C. 25 , 50
- D. 30 , 45 Discuss
- 6. 15 liters of a mixture contains 20 % alcohol and the rest water. If 3 liters of water be mixed in it, the % of alcohol in the new mixture will be ?
Options- A. 17
- B. 16 2 3
- C. 18 1 2
- D. 15 Discuss
- 7. A dishonest milkman professes to sell his milk at C. P. But he mixes it with water and thereby gains 25 %. The % of water in the mixture is ?
Options- A. 25%
- B. 20%
- C. 4%
- D. None of these Discuss
- 8. In what ratio must a grocer mix sugar at 72 paise per kg with sugar at 48 paise per kg. So that by selling the mixture at
63 paise per kg he may gain 1 of his out-lay? 6
Options- A. 1 : 3
- B. 3 : 1
- C. 2 : 3
- D. 3 : 2 Discuss
- 9. A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained?
Options- A. 5:3
- B. 1:4
- C. 4:1
- D. 9:1 Discuss
- 10. 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water?
Options- A. 310 ml
- B. 320 ml
- C. 330 ml
- D. 340 ml Discuss
Alligation or Mixture problems
Search Results
Correct Answer: Rs. 9
Explanation:
According to question ,
Total C. P. of 200 kg of mixture = Rs. (80 × 6·75 + 120 × 8)
Total C. P. of 200 kg of mixture = Rs. 1500
Average rate = Rs. 7·50 per kg
Required rate = 120% of Rs. 7·50
Required rate = Rs. 9 per kg.
Correct Answer: Rs. 18
Explanation:
Correct Answer: Rs. 2000
Explanation:
Correct Answer: 34
Explanation:
Correct Answer: 20 , 55
Explanation:
Average money per head (boy or girl) = Rs. (675 / 75) = Rs. 9
Number of boys = 4 / (4 + 11) × 75 = 20
Number of girls = 11 / (4 + 11) × 75 = 55.
Correct Answer: 16 2 3
Explanation:
Correct Answer: 20%
Explanation:
Correct Answer: 1 : 3
Explanation:
Correct Answer: 9:1
Explanation:
According to question,
Quantity of Milk/Quantity of Water = 3/2
Let us assume the product ratio = n.
Quantity of Milk = 3n and Quantity of Water = 2n liters
Quantity of Milk + Quantity of Water = 20 liters
3n + 2n = 20 liters
5n = 20 liters
n = 20/5
n = 4
Quantity of Milk = 3n liters
Put the value of n,
Quantity of Milk = 3 x 4 = 12 liters
Quantity of Water = 2n
Quantity of Water = 2 x 4 = 8 liters
If 10 liters of mixture are removed first time, we will find how much milk and water contain in mixture.
? 20 liters of mixture contains 12 liter of milk.
? 1 liters of mixture contains 12/20 liter of milk.
? 10 liters of mixture contains 10 x 12/20 liter of milk.
? 10 liters of mixture contains 6 liter of milk.
? 10 liters of mixture contains 4 liter of water.
If 10 liters of mixture are removed, then amount of milk removed = 6 liters and amount of water removed = 4 liters.
Remaining milk = 12 - 6 = 6 liters
Remaining water = 8 - 4 = 4 liters
10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters and water = 4 liters.
If the process is repeated one more time and 10 liters of the mixture are removed second time, then
If 10 liters of mixture are removed, Again we will find how much milk and water contain in the mixture.
? 20 liters of mixture contains 16 liter of milk.
? 1 liters of mixture contains 16/20 liter of milk.
? 10 liters of mixture contains 10 x 16/20 liter of milk.
? 10 liters of mixture contains 8 liter of milk.
? 10 liters of mixture contains 2 liter of water.
If 10 liters of mixture are removed, then amount of milk removed = 8 liters and amount of water removed = 2 liters.
Remaining milk = (16 - 8) = 8 liters.
Remaining water = (4 - 2) = 2 liters.
Now 10 liters milk is added => total milk = 18 liters and water will be 2 liters.
The required ratio of milk and water in the final mixture obtained
Quantity of milk/Quantity of Water= 18:2 = 9:1
Correct Answer: 320 ml
Explanation:
Let us assume the ratio product is Q.
According to question,
Quantity of Milk in mixture = 6Q ml
Quantity of Water in mixture = 2Q ml
Quantity of Milk in mixture + Quantity of Water in mixture = 640
6Q + 2Q = 640
8Q = 640
Q = 640/8
Q = 80
Quantity of Milk in mixture = 6Q ml = 6 x 80 = 480 ml
Quantity of Water in mixture = 2Q ml = 2 x 80 = 160 ml
To find the new mixture containing half milk and half water,
Quantity of water to be added for making the mixture of equal quantity of milk and water = 480 - 160 = 320
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