Salaries of Akash, Bablu and Chintu are in the ratio of 2 : 3 : 5. If their salaries were increased by 15%, 10% and 20% respectively, then what will be the new ratio of their salaries?

2A/5 + 40 = 2B/7 + 20 = 9C/17 + 10 = K
Then, A = (5/2) x (K - 40), B = (7/2) x (K - 20), C = (17/9) x (K - 10)

According to the question, A + B + C = 600
? (5/2) x ( K - 40) + (7/2) x (K - 20) + (17/9) x (K - 10) = 600
? 45 x (K - 40 ) + 63 x (K - 20) + 34 x (K - 10) = 10800
? 45K - 1800 + 63K - 1260 + 34K - 340 = 10800
? 142K - 3400 = 10800
? 142K = 10800 + 3400
? 142K = 14200
? K = 14200/142 =100
? B = (7/2) x (K - 20) = (7/2) x (100 - 20)
= (7 x 80)/2 = 7 x 40
= ? 280

According to the question.
(46k +30) + (41k + 30) + (34k + 25) = 2505
? 121k = 2505 - 85 = 2420
? k = 2420/121 = 20
? Number of coins received by Parat = 41k + 30
= 41 x 20 + 30 = 850

let the number of adult men be N.
Then, ratio of the numbers of adult men and adult women
9 : 7 = N : 4.2
? N = (9/7) x 4.2 = 5.4 Lakh
Total adult population = 4.2 + 5.4 = 9.6 lakh.

If the population of the town be M Lakh,
then, 80M/100 = 9.6
? M = (9.6 x 100)/80 = 12 lakh

1/2A = 1/3B =1/6C = x
? A = 2x, B = 3x, C =6x
? A : B : C = 2 : 3 : 6
Third part = Rs. (1870 x 6/11) = Rs. 1020

Milk = 85 x (27/34) kg = 135/2 kg = 67.5 kg
Water = 85 x (7/34) kg = 35/2 kg = 17.5 kg

Let Amount of water to be added is x,
? 67.5 / (17.5 + x) = 3/1
? 3 (17.5 + x) = 67.5
? x =5
? Water to be added = 5 kg.

According to the question
Expenses ? (income)²
? 9000 = K (15000 )²
? K = 9000/(15000)²
= 1/25000
Again E = K x 1²
? 1 = K x 1² [? exenses = income]
? 1 = 1/K = 25000
? Required answer = ? 25000

4 leaps of cat = 3 leaps of dog
? 1 leap of cat = 3/4 leap dog
Cat takes 5 leaps for every 4 leaps of dog
? Required ratio = (5 x Cat's leap ) : ( 4 x Dog's leap)
= (5 x 3/4 dog's leap) : (4 x Dog's leap)
= 15 : 16

Let monthly income of Sita Riya and Kunal be 84k, 76k and 89k, respectively.
Given annual income of Riya = 456000
? Monthly income of Riya = 456000/12 = 38000
? 76k = 38000 ? k = 500

So, the monthly income of Sita and Kunal = 84k + 89k = 173k
= 173 x 500 = 86500

Therefore, annual income = 86500 x 12 = ? 1038000

Amount given to A= 9k + 26
Amount given to B = 13k + 28
and amount given to C = 8k + 32

According to the question,
(9k + 26) + (13k + 28) + (8k + 32) = 2186
? 30 k + 86 = 2186
? 30 k = 2100
? k = 70

Hence, amount given to A = 9k + 26 = 9 x 70 + 26
= 630 + 26 = ? 656

Let the person have ? N
Then shares of elder don = ? 2N/5
and share of younger son = ? 3N/10

According to the question,
2N/5 - 3N/10 = 2000
? N/10 = 2000
? N = 20000

Remaining amount saved in trusts
= 1 - (2N/5 + 3N/10 ) = 1 - (4N + 3N)/10
= 1 - 7N/10 = 3N/10 x 20000 = 6000

given that A : B : C = 3 : 5: 2
? Share of C = [2/(3 + 5 +2)] x 6000
= (2/10) x 6000 = ? 1200