Ratio of salaries
Akash : Babloo : Cintu 2 : 3 : 5
Let the common ratio be 'k'
Then, salaries of Akash, Babloo and chintu will be 2k, 3k and 5k, respectively.
Now, 15% increase in Akash's salary = 15% of 2k
= 15 x 2k/100 = 0.3k
New salary = 2k + 0.3k = 2.3k
Also, 10% increase in Babloo's salary = 10% of 3k
= 10 x 3k/100 = 0.3k
? New salary = 3k + 0.3k = 3.3k
Again, 20%increase in Chintu's salary = 20% of 5k
= 20 x 5k/100 = 1k
New salary = 5k + k = 6k
? New ratio = Ratio of new salaries = 2.3k : 3.3k : 6k
On multiplying with 10 and dividing by k ratio will be 23 : 33 : 60.
Let the sum be ? P .
Then, CI when compounded half - yearly = [P x (1 + 10/100)4 - P] = 4641P/10000
CI when compounded annually = [ P x (1 + 20/100)2 - P] = 11P/25
According to the question, 4641P/10000 - 11P/25 = 964
? [(4641 - 4400)/10000] x P = 964
? P = (964 x 10000)/241
= ? 40000
Ratio of times taken by A and B = 160 : 100
A can do the work in 12 days
Let B can do the work in "D" days
=> 160:100 = 12 : D
=> D = 12 x 100/160 = 7.5 hrs
3/15 + 4/16 + x/24 = 1
Time taken to fill 2/7 = 1
Then to fill full 1 = ?
? = 1/(2/7) = 7/2 minutes.
Let M, N and O worked together for x days.
From the given data,
M alone worked for 8 days
M,N,O worked for x days
N, O worked for 1 day
But given that
M alone can complete the work in 18 days
N alone can complete the work in 36 days
O alone can complete the work in 54 days
The total work can be the LCM of 18, 6, 54 = 108 units
M's 1 day work = 108/18 = 6 units
N's 1 day work = 108/36 = 3 units
O's 1 day work = 108/54 = 2 units
Now, the equation is
8 x 6 + 11x + 5 x 1 = 108
48 + 11x + 5 = 108
11x = 103 - 48
11x = 55
x = 5 days.
Hence, all M,N and O together worked for 5 days.
Given for year = 70000
=> 365 days = 70000
=> 365 x 24 hours = 70000
=> 1 hour = ?
70000/365x24 = 7.990 = 8
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.