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- Question
- The ratio of 1st and 2nd classes train fairs between two stations is 3 : 1 and that of the number of passengers travelling between these stations by 1st and 2nd classes is 1 : 50. If on a particular day, ? 2650 be collected from the passengers travelling between these stations, then find the amount collected from 2nd class passengers.
Options- A. ? 3000
- B. ? 3500
- C. ? 2800
- D. ? 2500
- Correct Answer
- ? 2500
ExplanationRatio of the amounts collected from 1st and 2nd classes fairs = (3 x 1) ; (1 x 50) = 3 : 50
? Amount collected from 2nd class
Passengers = 2650 x (50/53) = ? 2500 - 1. ? 710 were divided among A, B and C in such a way that A had ? 40 more than B and C had ? 30 more than A. How much was C's share?
Options- A. ? 270
- B. ? 300
- C. ? 135
- D. ? 235 Discuss
- 2. ? 5625 are divided among A, B and C so that A receives 1/2 as much as B and C together receive and B receives 1/4 as much as A and C together receive. Find the sum of shares of A and B.
Options- A. ? 5000
- B. ? 3000
- C. ? 15000
- D. ? 9000 Discuss
- 3. If the position of the digits of a two-digit number are interchanged, the number newly formed is smaller than the original number by 45. Also, the ratio of the new number to the original number is 3 : 8, What is the original number?
Options- A. 61
- B. 72
- C. 94
- D. None of these Discuss
- 4. Salary of Mr. X is 80% of the salary of Mr. Y and salary of Mr. Z is 120% of the salary of Mr. X. What is the ratio between the salaries of X, Y and Z respectively?
Options- A. 4 : 6 : 5
- B. 4 : 5 : 6
- C. 16 : 24 : 25
- D. None of these Discuss
- 5. A sum of the ? 300 is divided among P, Q and R in such a way that Q gets ? 30 more than P and R gets ? 60 more then Q. Then, ratio of their shares is?
Options- A. 2 : 3 : 5
- B. 3 : 2 : 5
- C. 2 : 5 : 3
- D. 5 : 3 : 2 Discuss
- 6. Out of two sections A and B, 10 students of section B shift to A, as a result strength of A becomes 3 times the strength of B. But , if 10 students shift over from A to B, both A and B become equal in strength. Ratio of the number of students in section A that of section B is?
Options- A. 2 : 1
- B. 5 : 3
- C. 3 : 1
- D. 9 : 4 Discuss
- 7. A sum of money is to be divided equally among P, Q and R in the respective ratio of 5 : 6 : 7 and another sum of money is to be divided between S and T equally. If S got ? 2100 less than P, then how much amount did Q receive?
Options- A. ? 2500
- B. ? 2000
- C. ? 1500
- D. Couldn't be determined Discuss
- 8. Nandita scores 80% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105, How many marks did Nandita score in Science, if she scored 89 marks in Hindi, 92 marks in Sanskrit, 98 marks in Mathematics and 81 marks in English?
Options- A. 60
- B. 75
- C. 65
- D. 70 Discuss
- 9. Number of employees in a factory decreases in the ratio of 8 : 7 and salary of employees increases in the ratio of 5 : 6 . Find whether the total salary given to the employee is increasing or decreased and in What ratio?
Options- A. 19 : 20 increased
- B. 20 : 19 decreased
- C. None of above
- D. 21 : 20 decreased Discuss
- 10. Out of 120 applications for a post, 70 are males and 80 have a driver's licences . What is the ratio between the minimum to maximum number number of males having driver's license?
Options- A. 1 : 3
- B. 2 : 3
- C. 3 : 7
- D. 5 : 7 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: ? 270
Explanation:
Let B gets x.
Then, A gets (x + 40) and C gets (x + 70).
According to the question,
x + 40 + x + x + 70 = 710
? 3x = 710 - 110 = 600
? x = 600/3 = 200
? C's share = 200 + 70 = ? 270
Correct Answer: ? 3000
Explanation:
Accoridng to rhe question
A = ( B + C)/2
? B + C = 2A
? A + B + C = 3A (adding A on both sides)
? 3A = 5625
? A = 5625/3 = ? 1875 ....(i)
Again from question B = (A + C)/4
? A + C = 4B
? A + B + C = 5B (adding B on both sides)
? 5B = 5625
? B = 5624/5 = ? 1125 ...(ii)
From (i) and (ii)
? A + B = 1875 + 1125 = ? 3000
Correct Answer: 72
Explanation:
According to the question.
8N - 3N = 45 ? 5N =45
? N = 45/5 = 9
? Orignal number = 8N = 8 x 9 = 72
Correct Answer: 4 : 5 : 6
Explanation:
Let Y's salary = 100
? X's salary = 80
and Z's salary = 80 x (120/100) = 96
? Required ratio = 80 : 100 : 96 = 20 : 25 : 24
Correct Answer: 2 : 3 : 5
Explanation:
Let the share of P = x
Then, Q's share = x + 30 and
R's share = (x + 30) + 60 = x + 90
Sum of money with P, Q and R = 300
? x + (x + 30) + (x + 90) = 300
? 3x + 120 = 300
? x = (300 - 120)/3 = 60
? Required ratio = 60 : (60 + 30) : (60 + 90) = 2 : 3 : 5
Correct Answer: 2 : 1
Explanation:
A +10 = 3(B - 10)
? A - 3B = -20 ....(i)
And ( A - 10) = (B + 10)
? A - B = 20 ...(ii)
on subtracting Eq.(ii) from Eq.(i), we get
(A - 3B) - (A - B) = -20 - 20
? - 2B = - 40
there4; B = 20
Now, by using Eq. ...(ii),
there4; Ratio of the numbers of students of A and B = 40 : 20 = 2 : 1
Correct Answer: Couldn't be determined
Explanation:
Couldn't be determined, since the total amount of money is not given in either of the case
Correct Answer: 60
Explanation:
Total of maximum marks of all subjects = 105 x 5 = 525
Total marks obtained by Nandita = 80% of 525 = 525 x 80/100 = 420
Obtained marks of four subjects (Hindi, Sanskrit, Mathematics and English)
= 89 + 92 + 98 + 81 = 360
So, the obtained marks in Science = 420 - 360 = 60
Correct Answer: None of above
Explanation:
Let total number of employees in beginning = 8K and total number of employees in present = 7K
Let salary of an employee in beginning = 5L and salary of an employee in present = 6L
? Total salary in beginning = 8K x 5L = 40KL
and total salary in present = 7K x 6L = 42 KL
Required ratio = 40KL : 42KL = 20 : 21
Clearly, salary is increased.
Correct Answer: 3 : 7
Explanation:
Since there are 70 males out of 120 applicants, there must be 50 females out must have For the minimum number of males to have a driver's licence all 50 females must have a driver's license Thus the number of males having a driver's licence will be 80 - 50 = 30. The maximum possible number of males having a driver's license is 70. The ratio between the minimum and the maximum is 30 : 70 or 3 : 7 .
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