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- Question
- ? 5625 are divided among A, B and C so that A receives 1/2 as much as B and C together receive and B receives 1/4 as much as A and C together receive. Find the sum of shares of A and B.
Options- A. ? 5000
- B. ? 3000
- C. ? 15000
- D. ? 9000
- Correct Answer
- ? 3000
ExplanationAccoridng to rhe question
A = ( B + C)/2
? B + C = 2A
? A + B + C = 3A (adding A on both sides)
? 3A = 5625
? A = 5625/3 = ? 1875 ....(i)
Again from question B = (A + C)/4
? A + C = 4B
? A + B + C = 5B (adding B on both sides)
? 5B = 5625
? B = 5624/5 = ? 1125 ...(ii)
From (i) and (ii)
? A + B = 1875 + 1125 = ? 3000 - 1. If the position of the digits of a two-digit number are interchanged, the number newly formed is smaller than the original number by 45. Also, the ratio of the new number to the original number is 3 : 8, What is the original number?
Options- A. 61
- B. 72
- C. 94
- D. None of these Discuss
- 2. Salary of Mr. X is 80% of the salary of Mr. Y and salary of Mr. Z is 120% of the salary of Mr. X. What is the ratio between the salaries of X, Y and Z respectively?
Options- A. 4 : 6 : 5
- B. 4 : 5 : 6
- C. 16 : 24 : 25
- D. None of these Discuss
- 3. A sum of the ? 300 is divided among P, Q and R in such a way that Q gets ? 30 more than P and R gets ? 60 more then Q. Then, ratio of their shares is?
Options- A. 2 : 3 : 5
- B. 3 : 2 : 5
- C. 2 : 5 : 3
- D. 5 : 3 : 2 Discuss
- 4. Brother A and B had some saving in the ration 4 : 5. They decided to buy a gift for their sister, sharing the cost in the ratio 3 : 4, After they bought, A spent two- third of his amount, while B is left with ? 146, Then the value of the gift is?
Options- A. ? 70
- B. ? 105
- C. ? 140
- D. ? 175 Discuss
- 5. The marks of 3 students A, B and C are in the ratio 10 : 12 : 15. If the maximum marks of the paper are 100, then the marks of B cannot be in the range of?
Options- A. 20 - 30
- B. 40 - 50
- C. 70 - 80
- D. 80 - 90 Discuss
- 6. ? 710 were divided among A, B and C in such a way that A had ? 40 more than B and C had ? 30 more than A. How much was C's share?
Options- A. ? 270
- B. ? 300
- C. ? 135
- D. ? 235 Discuss
- 7. The ratio of 1st and 2nd classes train fairs between two stations is 3 : 1 and that of the number of passengers travelling between these stations by 1st and 2nd classes is 1 : 50. If on a particular day, ? 2650 be collected from the passengers travelling between these stations, then find the amount collected from 2nd class passengers.
Options- A. ? 3000
- B. ? 3500
- C. ? 2800
- D. ? 2500 Discuss
- 8. Out of two sections A and B, 10 students of section B shift to A, as a result strength of A becomes 3 times the strength of B. But , if 10 students shift over from A to B, both A and B become equal in strength. Ratio of the number of students in section A that of section B is?
Options- A. 2 : 1
- B. 5 : 3
- C. 3 : 1
- D. 9 : 4 Discuss
- 9. A sum of money is to be divided equally among P, Q and R in the respective ratio of 5 : 6 : 7 and another sum of money is to be divided between S and T equally. If S got ? 2100 less than P, then how much amount did Q receive?
Options- A. ? 2500
- B. ? 2000
- C. ? 1500
- D. Couldn't be determined Discuss
- 10. Nandita scores 80% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105, How many marks did Nandita score in Science, if she scored 89 marks in Hindi, 92 marks in Sanskrit, 98 marks in Mathematics and 81 marks in English?
Options- A. 60
- B. 75
- C. 65
- D. 70 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 72
Explanation:
According to the question.
8N - 3N = 45 ? 5N =45
? N = 45/5 = 9
? Orignal number = 8N = 8 x 9 = 72
Correct Answer: 4 : 5 : 6
Explanation:
Let Y's salary = 100
? X's salary = 80
and Z's salary = 80 x (120/100) = 96
? Required ratio = 80 : 100 : 96 = 20 : 25 : 24
Correct Answer: 2 : 3 : 5
Explanation:
Let the share of P = x
Then, Q's share = x + 30 and
R's share = (x + 30) + 60 = x + 90
Sum of money with P, Q and R = 300
? x + (x + 30) + (x + 90) = 300
? 3x + 120 = 300
? x = (300 - 120)/3 = 60
? Required ratio = 60 : (60 + 30) : (60 + 90) = 2 : 3 : 5
Correct Answer: ? 140
Explanation:
let the saving of A and B are 4M , 5M and the share in cost of gift are 3N, 4N respectively
According to the question
for A, 4M - 3N = (2/3) x 4M
? M = 9N/4.............(i)
For B 5M - 4N = 145
? 5 x (9N/4) - 4N = 145 [by Eq. (i)]
? N = 20
? Cost of gift = 3N + 4N = 7 x 20 = ? 140
Correct Answer: 80 - 90
Explanation:
Let the marks of A, B and C are 10k, 12k and 15k, respectively.
Let k = 6
? Maximum marks of C can be = 15 x 6 = 90
So, maximum marks of B can be = 12 x 6 = 72
As the marks are fixed and they cannot exceed the maximum marks.
So, the marks of B cannot be in the range of (80 - 90) ie B cannot score above 80.
Correct Answer: ? 270
Explanation:
Let B gets x.
Then, A gets (x + 40) and C gets (x + 70).
According to the question,
x + 40 + x + x + 70 = 710
? 3x = 710 - 110 = 600
? x = 600/3 = 200
? C's share = 200 + 70 = ? 270
Correct Answer: ? 2500
Explanation:
Ratio of the amounts collected from 1st and 2nd classes fairs = (3 x 1) ; (1 x 50) = 3 : 50
? Amount collected from 2nd class
Passengers = 2650 x (50/53) = ? 2500
Correct Answer: 2 : 1
Explanation:
A +10 = 3(B - 10)
? A - 3B = -20 ....(i)
And ( A - 10) = (B + 10)
? A - B = 20 ...(ii)
on subtracting Eq.(ii) from Eq.(i), we get
(A - 3B) - (A - B) = -20 - 20
? - 2B = - 40
there4; B = 20
Now, by using Eq. ...(ii),
there4; Ratio of the numbers of students of A and B = 40 : 20 = 2 : 1
Correct Answer: Couldn't be determined
Explanation:
Couldn't be determined, since the total amount of money is not given in either of the case
Correct Answer: 60
Explanation:
Total of maximum marks of all subjects = 105 x 5 = 525
Total marks obtained by Nandita = 80% of 525 = 525 x 80/100 = 420
Obtained marks of four subjects (Hindi, Sanskrit, Mathematics and English)
= 89 + 92 + 98 + 81 = 360
So, the obtained marks in Science = 420 - 360 = 60
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