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- Question
- Salary of Mr. X is 80% of the salary of Mr. Y and salary of Mr. Z is 120% of the salary of Mr. X. What is the ratio between the salaries of X, Y and Z respectively?
Options- A. 4 : 6 : 5
- B. 4 : 5 : 6
- C. 16 : 24 : 25
- D. None of these
- Correct Answer
- 4 : 5 : 6
ExplanationLet Y's salary = 100
? X's salary = 80
and Z's salary = 80 x (120/100) = 96
? Required ratio = 80 : 100 : 96 = 20 : 25 : 24 - 1. A sum of the ? 300 is divided among P, Q and R in such a way that Q gets ? 30 more than P and R gets ? 60 more then Q. Then, ratio of their shares is?
Options- A. 2 : 3 : 5
- B. 3 : 2 : 5
- C. 2 : 5 : 3
- D. 5 : 3 : 2 Discuss
- 2. Brother A and B had some saving in the ration 4 : 5. They decided to buy a gift for their sister, sharing the cost in the ratio 3 : 4, After they bought, A spent two- third of his amount, while B is left with ? 146, Then the value of the gift is?
Options- A. ? 70
- B. ? 105
- C. ? 140
- D. ? 175 Discuss
- 3. The marks of 3 students A, B and C are in the ratio 10 : 12 : 15. If the maximum marks of the paper are 100, then the marks of B cannot be in the range of?
Options- A. 20 - 30
- B. 40 - 50
- C. 70 - 80
- D. 80 - 90 Discuss
- 4. If sum of ? 1664 is divided between P and Q in the ratio of 1/3 : 1/5, then find P's share?
Options- A. 1085
- B. 1015
- C. 1090
- D. 1040 Discuss
- 5. A bag contains ? 1, 50 paise and 25 paise coins in the ratio of 8 : 9 : 11. If the total money in the bag is ? 366, then find the number of 25 paise coins?
Options- A. 264
- B. 364
- C. 241
- D. 245 Discuss
- 6. If the position of the digits of a two-digit number are interchanged, the number newly formed is smaller than the original number by 45. Also, the ratio of the new number to the original number is 3 : 8, What is the original number?
Options- A. 61
- B. 72
- C. 94
- D. None of these Discuss
- 7. ? 5625 are divided among A, B and C so that A receives 1/2 as much as B and C together receive and B receives 1/4 as much as A and C together receive. Find the sum of shares of A and B.
Options- A. ? 5000
- B. ? 3000
- C. ? 15000
- D. ? 9000 Discuss
- 8. ? 710 were divided among A, B and C in such a way that A had ? 40 more than B and C had ? 30 more than A. How much was C's share?
Options- A. ? 270
- B. ? 300
- C. ? 135
- D. ? 235 Discuss
- 9. The ratio of 1st and 2nd classes train fairs between two stations is 3 : 1 and that of the number of passengers travelling between these stations by 1st and 2nd classes is 1 : 50. If on a particular day, ? 2650 be collected from the passengers travelling between these stations, then find the amount collected from 2nd class passengers.
Options- A. ? 3000
- B. ? 3500
- C. ? 2800
- D. ? 2500 Discuss
- 10. Out of two sections A and B, 10 students of section B shift to A, as a result strength of A becomes 3 times the strength of B. But , if 10 students shift over from A to B, both A and B become equal in strength. Ratio of the number of students in section A that of section B is?
Options- A. 2 : 1
- B. 5 : 3
- C. 3 : 1
- D. 9 : 4 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 2 : 3 : 5
Explanation:
Let the share of P = x
Then, Q's share = x + 30 and
R's share = (x + 30) + 60 = x + 90
Sum of money with P, Q and R = 300
? x + (x + 30) + (x + 90) = 300
? 3x + 120 = 300
? x = (300 - 120)/3 = 60
? Required ratio = 60 : (60 + 30) : (60 + 90) = 2 : 3 : 5
Correct Answer: ? 140
Explanation:
let the saving of A and B are 4M , 5M and the share in cost of gift are 3N, 4N respectively
According to the question
for A, 4M - 3N = (2/3) x 4M
? M = 9N/4.............(i)
For B 5M - 4N = 145
? 5 x (9N/4) - 4N = 145 [by Eq. (i)]
? N = 20
? Cost of gift = 3N + 4N = 7 x 20 = ? 140
Correct Answer: 80 - 90
Explanation:
Let the marks of A, B and C are 10k, 12k and 15k, respectively.
Let k = 6
? Maximum marks of C can be = 15 x 6 = 90
So, maximum marks of B can be = 12 x 6 = 72
As the marks are fixed and they cannot exceed the maximum marks.
So, the marks of B cannot be in the range of (80 - 90) ie B cannot score above 80.
Correct Answer: 1040
Explanation:
Given that P's share : Q 's share = 1/3 : 1/5 = 5 : 3
Here, a = 5, b = 3, N = 1664
P's share = a/(a + b) x N
? = 5/(5 + 3) x 1664 = (5/8) x 1664 = ? 1040
Correct Answer: 264
Explanation:
Let number of ? 1 coins = 8k
Number of 50 paise coins = 9k
Number of 25 paise coins = 11k
According to the question,
8k + 9k/2 + 11k/4 = 366
? 32k + 18k + 11k = 1464
? 61k = 1464
? k = 1464/61 = 24
? Number of 25 paise coins = 11k = 11 x 24 = 264
Correct Answer: 72
Explanation:
According to the question.
8N - 3N = 45 ? 5N =45
? N = 45/5 = 9
? Orignal number = 8N = 8 x 9 = 72
Correct Answer: ? 3000
Explanation:
Accoridng to rhe question
A = ( B + C)/2
? B + C = 2A
? A + B + C = 3A (adding A on both sides)
? 3A = 5625
? A = 5625/3 = ? 1875 ....(i)
Again from question B = (A + C)/4
? A + C = 4B
? A + B + C = 5B (adding B on both sides)
? 5B = 5625
? B = 5624/5 = ? 1125 ...(ii)
From (i) and (ii)
? A + B = 1875 + 1125 = ? 3000
Correct Answer: ? 270
Explanation:
Let B gets x.
Then, A gets (x + 40) and C gets (x + 70).
According to the question,
x + 40 + x + x + 70 = 710
? 3x = 710 - 110 = 600
? x = 600/3 = 200
? C's share = 200 + 70 = ? 270
Correct Answer: ? 2500
Explanation:
Ratio of the amounts collected from 1st and 2nd classes fairs = (3 x 1) ; (1 x 50) = 3 : 50
? Amount collected from 2nd class
Passengers = 2650 x (50/53) = ? 2500
Correct Answer: 2 : 1
Explanation:
A +10 = 3(B - 10)
? A - 3B = -20 ....(i)
And ( A - 10) = (B + 10)
? A - B = 20 ...(ii)
on subtracting Eq.(ii) from Eq.(i), we get
(A - 3B) - (A - B) = -20 - 20
? - 2B = - 40
there4; B = 20
Now, by using Eq. ...(ii),
there4; Ratio of the numbers of students of A and B = 40 : 20 = 2 : 1
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