Let the marks of A, B and C are 10k, 12k and 15k, respectively.
Let k = 6
? Maximum marks of C can be = 15 x 6 = 90
So, maximum marks of B can be = 12 x 6 = 72
As the marks are fixed and they cannot exceed the maximum marks.
So, the marks of B cannot be in the range of (80 - 90) ie B cannot score above 80.
Given that P's share : Q 's share = 1/3 : 1/5 = 5 : 3
Here, a = 5, b = 3, N = 1664
P's share = a/(a + b) x N
? = 5/(5 + 3) x 1664 = (5/8) x 1664 = ? 1040
Let number of ? 1 coins = 8k
Number of 50 paise coins = 9k
Number of 25 paise coins = 11k
According to the question,
8k + 9k/2 + 11k/4 = 366
? 32k + 18k + 11k = 1464
? 61k = 1464
? k = 1464/61 = 24
? Number of 25 paise coins = 11k = 11 x 24 = 264
Given total amount = ? 49500
Let part of Amit's investment = 4k
and part of sudesh's investment = 7k
According to the question
4k + 7k = 49500
? 11k = 49500
? k = 49500/11
? k = 4500
Hence investment of sudesh = 7k = 7 x 4500 = 31500
Let the income of two persons are 7k and 3k
Expenditure of first person = 7k - 300
Expenditure of second person = 3k - 300
According to the question,
(7k - 300)/(3k - 300) = 5/2
? 14k - 600 = 15k - 1500
? k = 900
Income of first person = 7k = 7 x 900
= ? 6300
Let the number be M and N
According to the question.
M/N = 2/3
? 3M = 2N
? 3M - 2N = 0 ...(i)
And (M + 9)/(N + 9) = 3/4
? 4M + 36 = 3N + 27
? 4M - 3N = -9 ...(ii)
Multiplying Ex. (i) by 4 and Eq. (ii) by 3 and subtracting, we get N = 27
Now, putting N = 27 in Eq. (i), we get 3M = 54
? M = 18
? Product of the given numbers = 27 x 18 = 486
let the saving of A and B are 4M , 5M and the share in cost of gift are 3N, 4N respectively
According to the question
for A, 4M - 3N = (2/3) x 4M
? M = 9N/4.............(i)
For B 5M - 4N = 145
? 5 x (9N/4) - 4N = 145 [by Eq. (i)]
? N = 20
? Cost of gift = 3N + 4N = 7 x 20 = ? 140
Let the share of P = x
Then, Q's share = x + 30 and
R's share = (x + 30) + 60 = x + 90
Sum of money with P, Q and R = 300
? x + (x + 30) + (x + 90) = 300
? 3x + 120 = 300
? x = (300 - 120)/3 = 60
? Required ratio = 60 : (60 + 30) : (60 + 90) = 2 : 3 : 5
Let Y's salary = 100
? X's salary = 80
and Z's salary = 80 x (120/100) = 96
? Required ratio = 80 : 100 : 96 = 20 : 25 : 24
According to the question.
8N - 3N = 45 ? 5N =45
? N = 45/5 = 9
? Orignal number = 8N = 8 x 9 = 72
Accoridng to rhe question
A = ( B + C)/2
? B + C = 2A
? A + B + C = 3A (adding A on both sides)
? 3A = 5625
? A = 5625/3 = ? 1875 ....(i)
Again from question B = (A + C)/4
? A + C = 4B
? A + B + C = 5B (adding B on both sides)
? 5B = 5625
? B = 5624/5 = ? 1125 ...(ii)
From (i) and (ii)
? A + B = 1875 + 1125 = ? 3000
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