Ratio of sides 1/3 : 1/4 : 1/5 = 20 : 15 : 12
Length of smallest side = 94 x (12/47) cm. = 24 cm.
? Remainder = Rs. [ 2430 - (5 + 10 + 15)] = Rs. 2400
&there4 A's share = Rs. [ (2400 x 3/12) + 5 ] = Rs. 605
Suppose C gets Re.1. Then B gets Re. (1/4)
? A gets = Re. (2/3 x 1/4) = Re. 1/6
? A : B : C = 1/6 : 1/4 : 1 = 2 : 3 : 12
Hence B's share = Rs. (680 x 3/17) = Rs. 120
? 1/5A : 1/8B = 3 : 4
? 8A/5B = 120/160
? A/B = 120/160 x 5/8 = 15/32
? First part = Rs. (94 x 15/47) = Rs. 30
? 5A = 3B = 2C = x
? A = x/5, B=x/3 and C =x/2
? A : B : C = x/5 : x/3 : x/2 = 6 : 10 : 15
Gold in C =(7/9 + 7/18) = 21/18 = 7/6
Copper in C = (2/9 + 11/18) = 15/18 = 5/6
? Gold : Copper = 7/6 : 5/6 = 7 : 5
Suppose C gets Rs. x
Then, B gets Rs. (x + 8) and A gets Rs. (x + 15)
? x + x + 8 + x + 15 = 53
? x =10
so, A : B : C = 25 : 18 : 10
A : B : C = 100 : 65 : 35 = 20 : 13 : 7
If C's share is Rs. 7, the sum is Rs. 40.
If C's share is Rs. 28, the sum is Rs.(40/7 x 28) = Rs. 160.
Let their incomes be 3x, 2x and expenditures 5y, 3y respectively.
Then, 3x - 5y = 1000 and 2x - 3y =1000.
Solving these equations we get x = 2000, y = 1000
? A's income = 3x = Rs.6000
Ratio of amounts collected from 1st and 2nd class = (4 x 1 : 1 x 40) = (1 : 10)
?Amount collection as 1st class fare = Rs. (1100 x 1/11) = Rs.100
Let the number of students be 2x, 3x and 5x
? (2x + 20) : (3x + 20) : (5x + 20) = 4 : 5 : 7
? (2x + 20)/4 = (3x + 20)/5 = (5x + 20)/7
? 5(2x + 20) = 4(3x + 20)
? x = 10
Hence, total number of student before increase = 10x = 100.
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