P2 + 4Q2 = 4PQ
? P2 + 4Q2 - 4PQ = 0
? (P - 2Q)2 = 0
? P - 2Q = 0
? P = 2Q
? P/Q = 2/1
? P : Q = 2 : 1
Required mean proportional = ?9 x 64
= 3 x 8 = 24
Let the 3rd proportional = k
Then, 15 : 30 : : 30 : k
? 15/30 = 30/k
? 15k = 30 x 30
? 15k = 30 x 30
? k = (30 x 30) / 15 = 60
Here, A : B = 2 : 3, B : C = 5 : 7 and C : D = 3 : 10
? A/D = (A/B) x (B/C) x (C/D)
= (2/3) x (5/7) x (3/10)
= 1/7
? A : D = 1 : 7
Given, P/Q = 8/15, Q/R = 5/8, R/S = 4/5
? P/S = (P/Q) x (Q/R) x (R/S)
? P/S = (8/15) x (5/8) x (4/5) = 4/15
? P : S = 4 : 15
Given that, P : Q = 8 : 15, Q : R = 3 : 2
P : Q : R = (8 x 3) : (15 x 3) : (15 x 2) = 24 : 45 : 30
? P : Q : R = 8 : 15 : 10
Here, consequent of first ratio should be equal to the antecedent of second ratio.
Given, P/Q = 7/5
? (5P - 2Q) / (3P + 2Q) = (5 x 7 - 2 x 5) / (3 x 7 + 2 x 5)
= (35 - 10) / (21 + 10)
= 25/31
Let 1st number be 4k and 2nd number be 7k.
According to the question,
(4k - 5) / (7k - 5) = 1/2
? 8k - 10 = 7k - 5
? 8k - 7k = 10 - 5
? k = 5
? Greater number = 7k = 7 x 5 = 35
Let required money be ? N.
Then,
(4/14) x N = 12
? N = (12 x 14)/4
= ? 42
Let the price of scooter = 8k and price of television = 7k
According to the question,
8k - 7k = 2000
? k = 2000
? Price of television = 7k = 7 x 2000
= ? 14000
Ratio of times taken = 1/2: 1/3
1/2 : 1/3 = y : 36
1/3y = 1/2 x 36
y=54 min
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