A has to pay the P.W. of Rs. 220 due 1 year hence, which is
= Rs. [ (100 x 220) / {100 + (10 x 1)} ] = Rs. 200
A, actually pays = Rs. [110 + P.W. of Rs. 110 due 2 years hence]
= Rs. [ 110 + (100 x 110) / {100 + (10 x 2)} ]
= Rs. [110 + 91.66] = Rs. [201.66]
? A loses = Rs. [200 - 201.66] = Rs. 1.66
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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