For an income of Rs. 4, investment = Rs. 96
For an income of Rs. 5, investment = Rs. (96/4) x 5 = Rs. 120
Cost price (CP) = 500
Selling Price (SP) = 576
Markup price (MP) = 900
Again SP = MP [( 1 - r/100)2] [r - rate of discount in %]
? 576 = 900 (1 - r/100)2
? 24/30 = (1 - r/100)
? r = 20%
Again, new SP = MP (1 + r/100)2
= 900 (1 + 20/100)2
= 1296
New, profit percentage = [(SP - CP)/CP] X 100
= [( 1296 - 500 ) / 500 ] x 100 = 159.2%
Given that container has 50 litres of milk.
After replacing 8 litres of milk with water for three times, milk contained in the container is:
= 29.63 litres.
Let x - 1046 - 398 - 69 = 999
Then x = 999 + 1046 + 398 + 69
= 2512.
Let the number be a and b .
Then, (a+b)2 = a2 + b2 + 2ab
= 289 + 2 x 120
= 289 + 240
= 529
? a+b = ?529 = 23
On dividing 13601 by 86, we get 29 as remainder
? Required number to be subtracted = 29.
Unit digit in 34 = 1
? Unit digit in ( 34 )16 = 1
? Unit digit in 365 = 3
Unit digit in 659 = 6
Unit digit in 771 = 3
? Required unit digit = Unit digit in ( 3 x 6 x 3 )
= Unit digit in 54
= 4
Let 232 = x and let ( 232 + 1 ) = ( x + 1 )
( 296 + 1 ) = ( x3 + 1 ) = ( x + 1 )( x2 -x + 1 )
Which is clearly divisible by n as ( x + 1 ) is divisible by n.
The number is of the form (5x + 3 ) where x is an integer
? [(5x + 3)2] / 5 = ( 25x2 + 30x + 9) / 5
= 25x2/ 5 + 30x/5 + (5 +4)/5
? The remainder is 4.
Let the two-digit number be 10x + y
10x + y = 7(x + y)
? x = 2y ...(i)
10(x +2 ) + (y + 2) = 6(x + y + 4) + 4
or 10x + y + 22 = 6x + 6y + 28
? 4x - 5y = 6 ...(ii)
Solving equations (i) and (ii)
We get x = 4 and y = 2
Let the numbers of diaries (produced) be 100 and the cost price of a diary be Rs. 1 then
Total cost incurred = 100 x 1 = 100
Total sale price = 32 x 0.75 + 60 x 1.4 = 108
Therefore profit = Rs. 8
Thus there is 8% profit.
Note : Marked price (i.e. expected) = 40% above the cost price.
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