Men, women and children are employed to do a work in the proportion of 3 : 2 : 1 and their wages as 5 : 3 : 2. When 90 men are employed, total daily wages of all amounts to ? 10350. Find the daily wages of a man.

Let the wages of 1 man, 1 woman and 1 boy are ? P, ? Q and ? R, respectively. According to the question,
3P + 2Q + 4R = 26 ....(i)
3P = 4Q ....(ii)
and 2Q = 3R ....(iii)

From Eqs. (i) and (ii), we get
4Q + 2Q + 4R = 26
? 6Q + 4R = 26.........................(iv)

From Eqs. (iii) and (iv), we get
9R + 4R = 26
? 13R = 26
? R = 2
From Eqs. (ii) and (iii), we get
Q = 3 and P = 4

? Wages of 4 men, 3 women and 2 boys
= (4 x 4) + (3 x 3) + (2 x 2)
= 16 + 9 + 4 = ? 29

Amount received by ( A + B + C) per day
= 5400/36 = ? 150
? A + B + C = ? 150.................(i)
Similarly, amount received by (A + C) per day
= 1880/20 = ? 94
? A + C = ? 94 ........................(ii)
Amount received by (B + C) per day
= 3040/40 = ? 76
? B + C = ? 76 ........................(iii)
From Eqs. (i) and (iii), we get
A + 76 = ? 150
A = 150 - 76 = ? 74
By putting the value of A in Eq. (ii), we get
74 + C = ? 94
? C = 94 - 74 = ? 20
Hence, amount received by C per day
= ? 20

Let the number of days to complete the work be N.
According to the question,
k/20 + (k - 2)/24 + (k - 5)/ 30 = 1
? [6k + 5(k - 2) + 4(k - 5)] / 120 = 1
? 6k + 5k + 4k = 120 + 10 + 20
? 15k = 150
? k = 10
? Work done by A = 10/20 = 1/2
? Share of A from the assured money
= (1/2) x 5400
= ? 2700

Ramesh's 1 day's work = 1/12
Suresh's 1 day's work = 1/16
(Ramesh + Suresh)'s 1 day work = (1/12) + (1/16)
= (16 + 12) / (12 x 16)
= 28/192
= 7/48

Given that, (Ramesh + Suresh + Boy)'s
1 day's work = 1/6
? Boy's 1 day's work = (1/6) - (7/48) = (8 - 7)/ 48 = 1/48
? Ramesh's share : Suresh's share : Boy's share = 1/12 : 1/16 : 1/48
= (8/96) : (6/96) : (2/96)
= 8 : 6 : 2
= 4 : 3 : 1

Let Ramesh's share be 4k , Suresh's share be 3k and boy's share be k.
According to the question,
4k + 3k + k = 800
8k = 800
? k = 800/8 = 100

? Ramesh's share = 4k = 4 x 100 = ? 400
Suresh's share = 3k = 3 x 100 = ? 300
Boy's share = k = ? 100

A's 1 day's work = 1/15
B's 1 day's work = 1/20
C's 1 day's work = 1/25

A, B and C worked together.
? (A + B + C)'s 1 day's work = (1/15) + (1/20) + (1/25)
= (20 + 15 + 12)/ 300
= 47/300

Days taken to complete work by A, B and C working together = 300/47

? Share of C = (1/25) x (300/47) x 47000
= ? 1200

Let man be represented by m and woman be represented by w.
? 2m + 1w = 1/14
? 14 x (2m + 1w ) = 1 ...(i)

and 4w + 2m = 1/8
8 x (4w + 2m) = 1 ...(ii)

On equating Eqs. (i) and (ii), we get
14 (2m + 1w) = 8 (4w + 2m)
? 28m + 14w = 32w + 16m
? 28m - 16m = 32w - 14w
? 12m = 18w
? m/w = 18/12 = 3/2
So, efficiency of 1 man and 1 woman is 3 : 2.
So, their wages must be in the same ratio
90/x = 3/2
[here, x = wages of a woman ]
? x = 90 x 2 / 3 = ? 60

Work for 1 st 2 days = (1/8) + (1/12) = 5/24
? Work for 8 days = (5/24) x (8/2) = 5/6
? Remaining work = 1- (5/6) = (6 - 5) / 6 = 1/6
On 9th day, A's work = 1/8

Remaining work after 9 days = (1/6) - (1/8) = (4 - 3) / 24 = 1/24
B will finish this work in (12 x 1)/24 = 1/2 day
Clearly, A worked for 5 days from starting.

? Work done by A in 5 days = (1/8) x 5 = 5/8
? A's share = (5/8) x 1280 = 5 x 160 = ? 800

? In 5 days , (4 men + 6 women ) get ? 1600.
? In 1 day, (4 men + 6 women) get ? 1600/5 = ? 320 ....(i)

In 1 day number of person to get ? 1 = 320 / 4 men + 6 women ....(ii)

Similarly, in second condition,
In 1 day, number of person to get ? 1 = (1740 / 6) x (3 men + 7 women)
= 290 / (3 men + 7 women) ....(iii)

From Eqs. (ii) and (iii), we get
320 / (4 men + 6 women) = 290 / (3 men + 7 women)
96 men + 224 women = 116 men + 174 women
? 20 men = 50 women
? Man / Women = 5/2
? 1 women = 2/5 man
From Eq. (i), 1 day,
(4 men + 6 women) = (4 men + 6 x 2/5 men) = 32/5 men get ? 320
? In 1 day, 1 man get = 320 x 5 /32 = ? 50
? In 1 day, 1 woman get = 50 x 2/5 = ? 20
? In 1 day, (7 men + 6 women) get
7 x 50 + 6 x 20 = ? 470
? Required number of days = 3760 / 470 = 8 days