A, B and C contract to do a work for ? 4200. A can do the work in 6 days, B in 10 days and C in 12 days.
From given question, As we know that
A can do the work in 6 days.
A can do 1/6 work in one day.
B can do the same work in 10 days.
B can do 1/10 work in one day.
C can do the same work in 12 days.
C can do 1/12 work in one day.
Work done shared by A : B : C = 1/6 : 1/10 : 1/12
Multiply by 60, we will get,
Work done shared by A : B : C = 10 : 6 : 5
Let us assume ration variable is P.
According to question,
10P + 6P + 5P = 4200
? 21P = 4200
? P = 200
A's share = 10P = 10 x 200 = ? 2000
B's share = 6P = 6 x 200 = ? 1200,
C's share = 5P = 5 x 200 = ? 1000
? Speed = Distance / Time = (300/15)
= 20 m/sec
= (20 x 18) / 5 = 72 km/hr
Ratio of the areas = area of original square / area of new square
= [ d2 / 2 ] / [ (2d)2 / 2 ] = 1/4
? New area becomes 4 fold.
So, 24 is wrong, it should be 8 (48/6 = 8).
Solving the two equations, we get: l = 63 and b = 40.
∴ Area = (l x b) = (63 x 40) m2 = 2520 m2.
Let the number be x,
Then, 4x/5 - 2x/3 = 8
? (12x - 10x) / 15 = 8
? 2x = 120
? x = 60
39°
Share of Rakesh : Share of Dinesh : Share of Mahesh
= 5000 : 8000 : 12000 = 5 : 8 : 12
Total earned profit = ? 12500
? Share of Dinesh in profit
= [8/(5 + 8 + 12)] x 12500 = (8/25) x 12500
= 8 x 500 = ? 4000
Let required number be 90k + 4, which is multiple of 7.
Least value of k for which (90k + 4) is divisible by 7 is k = 4.
∴ Required number = (90 x 4) + 4 = 364.
⟹ log (33 ) = 1.431
⟹ 3 log 3 = 1.431
⟹ log 3 = 0.477
∴ log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
∴ Required number of ways | = (3C1 x 6C2) + (3C2 x 6C1) + (3C3) | |||||||||||||
|
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= (45 + 18 + 1) | ||||||||||||||
= 64. |
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