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- Question
- A trader purchases a watch and a wall clock for ? 390. He sells them making a profit of 10% on the watch and 15% on the wall clock. He earnes a profit of ? 51.50. The difference between the original prices of the wall clock and the watch is equal to
Options- A. ? 110
- B. ? 100
- C. ? 80
- D. ? 120
- Correct Answer
- ? 110
ExplanationLet cost price of a wall clock = ? N
? Cost price of a watch = ? (390 - N)
According to the question,
{(N x 10)/100} + {(390 - N) x 15}/100 = 51.50
? 390 x 15 - 5N = 51.50 x 100
? 5N = 5850 - 5150 = 700
? N = 700/5 = 140
? Required difference = (390 - N) - N
= 390 - (2 x 140)
= 390 - 280 = 110
= ? 110 - 1. An article passing through two hands is sold at a profit of 40% at the original cost price. If the 1st dealer makes a profit of 20%, then the profit per cent made by the second is
Options- A. 151/3%
- B. 151/3%
- C. 162/3%
- D. 132/3% Discuss
- 2. A merchant buys p apples for ? q and sells q apples for ? p. If p < q, then in the whole outlay, he makes.
Options- A. 10(p2 + q2/q2)% gain
- B. 100 (q2 - p2/q2)% loss
- C. 100 (p2 + q2/p2)% loss
- D. 100 (q2 - p2/p2)% gain Discuss
- 3. A dishonest dealer purchases goods at 20% discount of the cost price of Rs. x and also cheats his wholesaler by getting 20% extra through false weighing, per kg. Then he marks up his goods by 80% of x, but he gives a discount of 25% besides he cheats his customer by weighing 10% less than the required. What is his overall profit percentage?
Options- A. 125% 120%
- B. 100%
- C. 98.66%
- D. 120% Discuss
- 4. A trader marks up his goods by 80% and gives discount of 25%. Besides it he weighs 10% less amount while selling his goods. What is the net profit of trader?
Options- A. 50%
- B. 35%
- C. 45%
- D. 55% Discuss
- 5. Radhey Lal markup the prices of sweets by 40% and he sold only 40% of those at this price. He sells half of the rest at 14 2/ 4% discount and rest at 25% discount. What is the net profit of Radhey Lal?
Options- A. 26.5%
- B. 23.5%
- C. 30%
- D. 28.6% Discuss
- 6. A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is
Options- A. 500 kg
- B. 600 kg
- C. 400 kg
- D. 640 kg Discuss
- 7. A dealer buys an article marked at ? 25000 with 20% and 5% off. He spends ? 2000 on its repair and sells it for ? 25000. What is his gain or loss per cent?
Options- A. 21% loss
- B. 10.50% loss
- C. 19.05% gain
- D. 25% gain Discuss
- 8. Cost of a packet of coffee powder and a litre of milk are ? 20 and ? 30 respectively. 10 cups of coffee is made with one packet coffee powder and for each cup 200 ml of milk is used. If coffee is sold at 25% profit, the selling price of each cup of coffee is
Options- A. ? 12.50
- B. ? 6.25
- C. ? 8
- D. ? 10 Discuss
- 9. A shopkeeper sells transistors at 15% above its cost price. If he had bought it at 5% more than what he paid for it and sold it for ? 6 more, he would have gained 10%. The cost price of the transistor is?
Options- A. ? 800
- B. ? 1000
- C. ? 1200
- D. ? 1400 Discuss
- 10. A merchant earns a profit of 20% by selling a basket containing 80 apples whose cost is ? 240 but he gives one-fourth of it to his friend at cost price and sells the remaining apples. In order to earn the same profit, at what price must he sell each apple?
Options- A. ? 3.00
- B. ? 3.60
- C. ? 3.80
- D. ? 4.80 Discuss
Profit and Loss problems
Search Results
Correct Answer: 151/3%
Explanation:
Let CP = ? 100
Then, SP = ? 140
Let the profit made by the 2nd dealer = N%
Then, (100 + N)% of 120% of ? 100 = ? 140
? [(100 + N)/100 x (120/100) ] / 100 = 140
? 6(100 + N) = 700
? 600 + 6N = 700
? 6N = 100
? N = (100/6)% = (50/3) %
= 162/3
Correct Answer: 100 (q2 - p2/q2)% loss
Explanation:
Given,
CP of p apples = q
? CP of 1 apple = q/p
and SP of q apples = p
? SP of 1 apple = p/q
Given, p < q
? Loss = q/p - p/q = (q2 - p2) / pq
And Loss% = (Loss/CP) x 100
= {(q2 - p2)/pq} /(q/p)] x 100
= (q2 - p2)/q2 x 100
Therefore, when p < q , then the person had a loos which is given by
100 x (q2 - p2/q2)% loss.
Correct Answer: 125% 120%
Explanation:
Let the actual cost price of an article be Rs.1 (in place of x)
Now the purchases goods worth Rs. 120 and pays Rs. 80, since 20% discount is allowed.
So the CP = 80/120 = 2/3
Again MP = 180, SP = 135 (since 25% discount)
Thus the trader sells goods worth Rs.90 instead of 100 g and charges Rs. 135. Therefore the effective SP = 135/90 = 3/2
Therefore Profit (%) = [(3/2 - 2/3 ) / (2/3)] x 100 = 125%
Correct Answer: 50%
Explanation:
Consider actual price of 1 g goods = Re. 1.
He sells the product equals to Rs. 90 only (10% less weighing)
Again MP = Rs.1.8 and SP = 1.35 for 1 g.
Thus he gives the goods worth Rs. 90 and charges Rs. 135 after 25% discount.
Thus the profit % = [(135 - 90) / 90 ] x 100
= 50%
Correct Answer: 23.5%
Explanation:
Let the number of the sweets be 100 and the cost price of the one piece of sweet = Re.1
Then, total cost price = 100 x 1 = Rs. 100
Total sale price = (40 x 1.4) + (30 x 1.2) + (30 x 1.05) =123.5
? Profit (%) = 123.5 - 100 = 23.5%
Correct Answer: 600 kg
Explanation:
Let the sugar sold at 8% gain = P
? Sugar sold at 18% gain = (1000 - P)
Let CP of sugar = ? Q per kg
Total CP = ? 1000 x Q
? [(108/100) x PQ)] + [(118/100) x (1000 - P) x Q]
= (114/100) x 1000 Q
? 108PQ + 118000Q - 118PQ = 114000Q
? 10P = 4000
? P = 400
? Quantity sold at 18% profit = 1000 - 400 = 600 kg
Correct Answer: 19.05% gain
Explanation:
Total CP = (95% of 80% of ? 25000) + (2000)
= (95/100) x (80/100) x 25000 + 2000
= 19000 + 2000 = ? 21000
? CP = ? 21000 and SP = ? 25000
? Gain = 25000 - 21000 = ? 4000
? Gain % = (4000/21000) x 100% = 400/21%
= 19.05% (approx.)
Correct Answer: ? 10
Explanation:
Cost of coffee powder used in one cup = 20/10 = ? 2
Cost of milk used in one cup = (30/1000) x 200 = ? 6
? Cost of each cup coffee = 2 + 6 = ? 8
To gain 25% profit, sale price of each cup of coffee = 125% of 8 = ? 10
Correct Answer: ? 1200
Explanation:
Let cost price of transistor = ? N
According to the question,
CP of transistor = (N x 105)/100
And SP of transistor = (115 x N)/100 + 6
? Profit percentage = (SP - CP)/CP x 100
? 10 = [[(115N/100) + 6 - (105N/100)] / (105N/100)] x 100
? 10 = [(10N + 600) x 100]/ 105N
? 105N = 100N + 6000
? 5N = 6000
? N= ? 1200
Correct Answer: ? 3.80
Explanation:
? CP of 80 apples = ? 240
? CP of 1 apples = ? 3
? CP of 20 apples = ? 60
To earn a profit of 20%
SP = 120% of 240 = ? 288
But he sales 1/4 of his apples i.e., 20 apples for ? 60
? SP of remaining 60 apples = 288 - 60 = ? 228
? SP of 1 apple = 228/60 = ? 3.80
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