A trader marks up his goods by 80% and gives discount of 25%. Besides it he weighs 10% less amount while selling his goods. What is the net profit of trader?

Let the number of the sweets be 100 and the cost price of the one piece of sweet = Re.1
Then, total cost price = 100 x 1 = Rs. 100
Total sale price = (40 x 1.4) + (30 x 1.2) + (30 x 1.05) =123.5
? Profit (%) = 123.5 - 100 = 23.5%

Let the numbers of diaries (produced) be 100 and the cost price of a diary be Rs. 1 then
Total cost incurred = 100 x 1 = 100
Total sale price = 32 x 0.75 + 60 x 1.4 = 108
Therefore profit = Rs. 8
Thus there is 8% profit.

Note : Marked price (i.e. expected) = 40% above the cost price.

You must know that the company is able to deliver only 90% of manufactured pens. So let k be the manufacturing price of a pen, then
Total income (including 25% profit) = 8000 x k x 1.25
Also this same income is obtained by selling 90% manufactured at Rs.10 which is equal to 7200 x 10.
Thus 8000 x K x 1.2 = 7200 x 10
? K = Rs. 7.2 ( 90% of 8000 = 7200)

From question, Chaudhary's profit = 10%.
So, Anupam's profit = 20%
Bhargava profit = 25%

Now Let cost price for Anupam = Rs. 100
So cost price for Bhargava = 120
Cost price for Chaudhary = 150
Cost price for Dara Singh = 165

Since the cost price for Dara singh is 2805 which is 17 times of 165. So the cost price for Bhargava is 120 x 17 = Rs. 2040.

Total cost price = 1000 x 1.2 = Rs. 1200
Expected selling price = 700 x selling price per toys = 1200 X 1.1666 = 1400
? Selling price per toys = Rs. 2 per toy
Now the real selling price = 750 x 2 = Rs.1500
? Profit = Rs. 300 = (1500 - 1200)
? Profit % = ( 300 / 1200 ) x 100 = 25%

Let the actual cost price of an article be Rs.1 (in place of x)
Now the purchases goods worth Rs. 120 and pays Rs. 80, since 20% discount is allowed.
So the CP = 80/120 = 2/3
Again MP = 180, SP = 135 (since 25% discount)
Thus the trader sells goods worth Rs.90 instead of 100 g and charges Rs. 135. Therefore the effective SP = 135/90 = 3/2

Therefore Profit (%) = [(3/2 - 2/3 ) / (2/3)] x 100 = 125%

Given,
CP of p apples = q
? CP of 1 apple = q/p
and SP of q apples = p
? SP of 1 apple = p/q

Given, p < q
? Loss = q/p - p/q = (q² - p²) / pq
And Loss% = (Loss/CP) x 100
= {(q² - p²)/pq} /(q/p)] x 100
= (q² - p²)/q² x 100

Therefore, when p < q , then the person had a loos which is given by
100 x (q² - p²/q²)% loss.

Let CP = ? 100
Then, SP = ? 140
Let the profit made by the 2nd dealer = N%
Then, (100 + N)% of 120% of ? 100 = ? 140
? [(100 + N)/100 x (120/100) ] / 100 = 140
? 6(100 + N) = 700
? 600 + 6N = 700
? 6N = 100
? N = (100/6)% = (50/3) %
= 16²/₃

Let cost price of a wall clock = ? N
? Cost price of a watch = ? (390 - N)
According to the question,
{(N x 10)/100} + {(390 - N) x 15}/100 = 51.50
? 390 x 15 - 5N = 51.50 x 100
? 5N = 5850 - 5150 = 700
? N = 700/5 = 140

? Required difference = (390 - N) - N
= 390 - (2 x 140)
= 390 - 280 = 110
= ? 110

Let the sugar sold at 8% gain = P
? Sugar sold at 18% gain = (1000 - P)
Let CP of sugar = ? Q per kg
Total CP = ? 1000 x Q
? [(108/100) x PQ)] + [(118/100) x (1000 - P) x Q]
= (114/100) x 1000 Q
? 108PQ + 118000Q - 118PQ = 114000Q
? 10P = 4000
? P = 400
? Quantity sold at 18% profit = 1000 - 400 = 600 kg