Total CP = 2 x 1200 = ? 2400
SP of 5% loss = (95/100) x 1200 = ? 1140
SP at 10% gain = (110/100) x 1200 = ? 1320
Total SP = 1140 +1320 = ? 2460
? Gain = 2460 - 2400 = ? 60
Gain % = (60/2400) x 100% = 2.5%
Original CP = [100/(100 + Gain%)] x SP
= (108/118) x 10207 = ? 8650
Let SP = ? 100
? CP = (3/10) x 100 = ? 30
New SP = (30 x 110)/100 = ? 33
Gain = 33 - 30 = ? 3
Gain % = (3/30) x 100% = 300/30 % = 10%
Let the selling price for the umbrella is P.
Cost price for the umbrella is Q.
Now from question
Q - 2P/3 = 10% of Q.
? P = (3/2)(Q - 10% of Q)
? P = (3/2) x (90/100) x Q
? P = 1.35 x Q.
So % profit = [(1.35 x Q - Q)/Q]x100 % = 35 % profit.
Let the actual price of per kg of wheat = ? . 100
Then, selling price = 110% of 100 = ? 110
Now, shopkeeper sell 20% less than actual weight so cost price to shopkeeper will be = 80% of 100
= (80 x 100)/100
= ? 80
Hence, required profit gained by shopkeeper = [(110 - 80)/80] x 100
= (30/80) x 100
= 37.5%
Gain percentage = [Error/(True value - Error)] x 100 %
= [(100/(1000 - 100)] x 100 %
= (100/900) x 100 %
= 111/9%
12 egg cost ? 30
Then cost price of 1 eggs = 35 x 12 = #8377; 2.5
Cost price of 100 eggs = 25 x 100 = ? 250
Now, let the SP of 100 eggs ? N.
Then [(SP - CP) / CP] x 100= profit % [(N - 250)/250] x 100 = 12
? (N - 250)/(2/5) =12
? N- 250 = (12 x 5)/2= 30
N = 250 + 30 = ? 280
CP of 1 orange for 1st rate = ? 1/4
CP of 1 orange for 2nd rate ? 1/5
CP of 2 orange after mixing = 1/4 + 1/5 = ? 9/20.
CP of 1 orange after mixing ? 9/20 X 2 = ? 9/40
SP Of 1 orange after mixing = ? 1/4
? Gain = 1/4 - 9/40 = ? 1/40
? Gain = (1/40 x 40/9 x 100)% = 100/9%
= 111/9%
Let CP of the article be ? N
Then, SP = 110% of x = 1.1N
If SP be double i.e., 2.2N, then
Profit per cent= [(2.2N - N)/ N] x 100% = 120%
Let CP = N, then gain = N/6
According to the question,
N + N/6 = 322
? 7N/6 = 322
? N = 322 x 6/7 = ? 276
let SP = N, then CP = 2N/3
Gain = (N - 2N/3) = N/3
&ther4; Gain % = [(N/3) / (2N/3)] x 100%
= (N/3) x (3/2N) x 100% = 50%
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