Gain percentage = [Error/(True value - Error)] x 100 %
= [(100/(1000 - 100)] x 100 %
= (100/900) x 100 %
= 111/9%
CP. = (80% of 90% of ?40000) + ?(1200)
= [(80/100) x (90/100) x 40000] + 1200
= (28800 + 1200)
= ?30000
? CP = ?30000
So, no gain no loss in the transaction.
Let the MP of a scooter = ? P
? CP of a scooter= ? 11P/13, Gain = 10%
SP = (110/100) x P= ? 11P/10
Gain = SP - CP = (11P/10 - 11P/13) = (143P - 110P)/130 = ? 33P/130
Gain percentage = (33P/130) x (13/11P) x 100 % = 30%
Let the CP be ? 100 and let MP be ? x above ? 100.
Then, MP = ? (100 + x) and discount =10%
? SP = [(90/100) x (100 + x)] = ? 177
? x = 30
So, cost should be labelled at 30% above CP.
CP = ? 180, gain = 20%
? SP = (120/100) x 180 = ? 216
Let the MP be ? P.
Then, 80% of P = 216
? (80/100) x P = 216
? P = (216 x 100)/80 = 270
Thus, MP is ? 270.
Let the fixed price of article = ?P
Then, Selling price = 90% of P = (90 x P)/100 = ? 9P/10
Also, the selling price = 115% of 72 = ?(115 x 72)/100
? (115 x 72)/100 = 9P/10
? P = ? 92
Let the actual price of per kg of wheat = ? . 100
Then, selling price = 110% of 100 = ? 110
Now, shopkeeper sell 20% less than actual weight so cost price to shopkeeper will be = 80% of 100
= (80 x 100)/100
= ? 80
Hence, required profit gained by shopkeeper = [(110 - 80)/80] x 100
= (30/80) x 100
= 37.5%
Let the selling price for the umbrella is P.
Cost price for the umbrella is Q.
Now from question
Q - 2P/3 = 10% of Q.
? P = (3/2)(Q - 10% of Q)
? P = (3/2) x (90/100) x Q
? P = 1.35 x Q.
So % profit = [(1.35 x Q - Q)/Q]x100 % = 35 % profit.
Let SP = ? 100
? CP = (3/10) x 100 = ? 30
New SP = (30 x 110)/100 = ? 33
Gain = 33 - 30 = ? 3
Gain % = (3/30) x 100% = 300/30 % = 10%
Original CP = [100/(100 + Gain%)] x SP
= (108/118) x 10207 = ? 8650
Total CP = 2 x 1200 = ? 2400
SP of 5% loss = (95/100) x 1200 = ? 1140
SP at 10% gain = (110/100) x 1200 = ? 1320
Total SP = 1140 +1320 = ? 2460
? Gain = 2460 - 2400 = ? 60
Gain % = (60/2400) x 100% = 2.5%
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.