Let the cost price of watch A = Rs. N
Then, cost price of watch B = Rs. (650 - N)
Now, selling price of watch A = (120 x N) / 100 = Rs. 6N/5
Also, selling price of watch B = (650 - N) x (75/100) = Rs. {3 x (650 - N)}/4
As, according to the question, two selling prices are equal.
? 6N/5 = {3 x (650 - N)}/4
? 8N = 5 x (650 - N)
? 8N + 5N = 5 x 650
? 13N = 5 x 650
? N = (5 x 650)/13 = 250
? Cost price of watch A = Rs. 250
and cost price of watch B = (650 - 250) = Rs. 400
Let the amount of juice and water in original mixture '4x' litre and '3x' litre respectively.
According to given data,
4x/3x+6 =8/7
28x=24x+48
28x?24x=48
4x = 48
x = 12
Amount of juice = 4x = 4×12 = 48 litre.
Ratio of milk andwater = 4:1
Quantity of water = 35/5 = 7 litres
Quantity of milk = 35 X 4/5 = 28 litres
If 7 litre of water is added, new quantity of water = 14 litre
New ratio of milk and water = 28:14 = 2:1
Let the number be N
According to the question
N - 3N/4 = 163
? N/4 = 163
? N = 652
Let initial quantity be Q, and final quantity be F
F = Q(1 - 8/Q)
=> Q = 20
2|64009( 253 |4 |---------- 45|240 |225 |---------- 503| 1509 | 1509 |---------- | X |----------∴ √64009 = 253.
So, the required number is -128.
? = 6.39 x 128.948 + 5.215 ÷ 12.189 + 25.056
= 639 x 128.948 + 5.215 x (1/12.189) + 25.056
= 823.97772 + 0.427844778 + 25.056
= 849.4615648 ? 852
By the formula, speed= Distance/ Time
= (240 + 240)/27 x (18/5)
= 480/27 x 18/5 = 64 km/h
1 / .003718 = 10000 / 3.718
= 10000 x ( 1/3.718)
= 10000 x .2689
= 2689.
Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%
? Number of days required by B = 100/6.66 = 15 days
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