Difference between two selling prices = 475 - 451 = Rs. 24
? 6% of C.P. = Rs. 24
Hence, C.P. = Rs. (24 x 100 / 6) = Rs. 400
? (115% of C.P.) - (125% of 90% of C.P.) = 4
? [115/100 - (125 x 90) / (100 x 100)] x CP = 4
? C.P. = Rs. 160
It is clear that (2.5% of C.P. + 7.5% of C.P.) = 100
? C.P. = Rs. 1000
Now, gain = 121/2
So, Required S.P. = 1121/2% of C.P.
= Rs. (225 / 200) x 1000
= Rs. 1125
? (20% of C.P.) - (16% of C.P.) = Rs. 20
? 4% of C.P. = 20
? (4/100 x C.P.) = 20
? C.P. = Rs. (100 x 20/4)
? C.P. of the bicycle = Rs. 500
Let us consider a packet of rice marked 1 kg
Then its actual weight = (80% of 1 kg) = 0.8 kg
Let C.P. of 1 kg be Rs. 100
Then C.P. of 0.8 kg = Rs. 0.8 x 100 = Rs. 80
Now, S.P of 1 kg = 110% of C.P.of 1 kg = Rs. 110
? Gain = (1.1 - 0.8) x 100 = 0.3 x 100 = 130
? Required gain% = [0.3/ (0.8 x 130)] x 100)%
= 37. 5%
C.P. of two horses = Rs. 8000
S.P. of one horse = Rs. 4000
Gain = 25%
? C.P. of this horse = Rs (100/125) x 4000 = Rs.3200
C.P. of another horse = Rs. (8000 - 3200) = Rs. 4800
S.P. of this horse = Rs. 4000
? Loss% = (800/4800) x 100 % = 162/3%
Total C.P.of 200 kg of sugar = Rs. (80 x 6.75 + 120 x 8)
= Rs. (500 + 960)
= Rs. 1460
C.P. of 1 kg = Rs. 1460 / 200 = Rs. 7.30
Gain required = 20%
? S.P. of 1 kg = (120% of Rs. 7.30)
= Rs. (120/100) x 7.30
= Rs. 8.76 per kg
Let the C.P. be Rs. x
Then 2(69 - x) / 100 = (78 - x) / 100
? 138 - 2x = 78 - x
? x = 60
? C.P. = Rs. 60
In such question we adopt the Required gain %
= [(100 + common gain%)2 / 100 - 100] %
= { (108)2/100 - 100 } % = 16.64%
Let the marked price be Rs. N
? C.P. = (N - 25% of N) = 3N / 4
? S.P. = (3N / 4 + 10% of 3N / 4) = 33N / 40
But, 33N / 40 = 660
? N = 800
Let original price = Rs. 100
Price after first discount = Rs. 90
Price after second discount = Rs. (80 x 90)/100 = Rs. 72
Price after third discount = Rs. (60 x 72)/100 = Rs. 43.20
? Single equivalent discount = (100 - 43.20) = 56.8%
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